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Ksenya-84 [330]

3 years ago

13

What is the value of 5+-12=

1 answer:

vitfil [10]3 years ago

6 0

Answer:

It would be -7

Step-by-step explanation:

The 12 is negative, so instead of adding, you would subtract 5.

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

√200 in consecutive integers and in simplified form

myrzilka [38]

√200 = √2·100 = √2 · √100 = 10√2

4 0

3 years ago

Expand the expression and combine like terms

____ [38]

But what is the expression, you have to tell me so I can do it.

4 0

3 years ago

Please I need help??

Ostrovityanka [42]

Answer:

Equation is cut out

Step-by-step explanation:

Upload a clear picture

7 0

3 years ago

If a=12 b=1 what is ab+20-b

Dmitriy789 [7]

Answer:

31

Step-by-step explanation:

(12)(1) + 20 - (1)

12 + 20 - 1

32 - 1

31

4 0

2 years ago

Read 2 more answers