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3 years ago

Could someone help what is the variable in “8y3”?

Mathematics

1 answer:

diamong [38]3 years ago

4 0

Answer:

Step-by-step explanation:

The variable in 8y^3 is y because a variable is a number that we don't know yet, and that is the only one.

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Rewrite the following equation in exponential form.<br> log 49(7) = 1/2

asambeis [7]

It would be log7squared(7)

4 0

3 years ago

Working at home: According to the U.S Census Bureau, 41% of men who worked at home were college graduates. In a sample of 506 wo

sergejj [24]

Solution :

a). The point estimate of proportion of college graduates among women who work at home,

$\hat p =\frac{166}{506}$

= 0.3281

99.5% confidence interval

$=\left( \hat p \pm Z_{0.005/2} \sqrt{\frac{\hat p (1- \hat p)}{n}} \right)$

$=\left( 0.3281 \pm 2.81 \sqrt{\frac{0.3281 \times (1- 0.3281)}{506}} \right)$

$=(0.3281 \pm 0.0586)$

$=(0.2695, 0.3867)$

6 0

3 years ago

It is given that p varies inversely as q. If p = 12 and q = 45 find p, if q is 135.

alexgriva [62]

Answer:

$p =4$

Step-by-step explanation:

Given

Variation: Inversely

$p = 12$ when $q = 45$

Required

Determine p when $q = 135$

First, we need to determine the relationship between p and q

Since, it is an inverse variation.

The relationship is:

$p\ \alpha\ \frac{1}{q}$

Convert to an equation

$p= k *\frac{1}{q}$

$p= \frac{k}{q}$

Where k = constant of variation

Make k the subject

$k = p * q$

When $p = 12$ and $q = 45$

$k = 12 * 45$

$k = 540$

To solve for p when q = 135

Substitute 135 for q and 540 for k in $p= \frac{k}{q}$

$p = \frac{540}{135}$

$p =4$

6 0

2 years ago

Classify the following triangle. Check all that apply.

11Alexandr11 [23.1K]

That is an isosceles right triangle. (Also known as a 45 45 90 triangle).

7 0

3 years ago

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Trevin puts 8 gallons of gas in his car and pays $22 What is the cost of 1 gallon of gas

Setler [38]

Answer:

1 gallon of gas is $2.75

Step-by-step explanation:

becuase 22 divided by 8 (since they put 8 gallons in) = 2.75

6 0

2 years ago

Read 2 more answers