Answer:
<em>The observed t (2.533) is in the tail cut off by the critical t (2.462), therefore we reject H0. It is likely that the books are older than 20 years of age on average.</em>
Step-by-step explanation:
<em>Step 1: Hypotheses and α level
</em>
H0: μ ≤ 20
H1: μ > 20
<u><em>α = 0.01</em></u>
<em>Step 2: Critical region
</em>
α = .01
One-tailed
df = n – 1 = 30 – 1 = 29
<u><em>t - critical = 2.462
</em></u>
<em>Step 3: Calculate t which is observed
</em>
sM = √(s2 / n) = √(67.5 / 30) = 1.5
t = (M – μ) / sM
t = (23.8 – 20) / 1.5
<u><em>t = 2.533
</em></u>
<u><em /></u>
Answer:
B) (2,-6)
Step-by-step explanation:
x-3x=4, x=2, plug 2 in for x y=-3*2 then, y=-6
H^2 = P^2 + B^2
a. 6^2 = 2^2 + 3^2
36 = 4 + 9
36 = 13
Therefore this is not a Pythagorean triple
b.5^2 = 4^2 + 3^2
25 = 16 + 9
25 = 25
Therefore this is a phythagorean triple
Compatible Numbers are numbers that are easy to divide mentally
It is 7. None of the other ones fit at all