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Alenkinab [10]
3 years ago
9

After losing your job, and needing cash fast, you decide to try

Mathematics
1 answer:
ra1l [238]3 years ago
8 0

Given:

The principal = $ 4000

The rate of interest = 22 %

To find the loan amount a) after 1 year and b) after 3 years.

Formula

Loan amount is

A = P(1+\frac{r}{100} )^{t}

where,

A be the loan amount

P be the principal

r be the rate of interest and

t be the time.

Now,

a) Taking, P = 4000, r = 22, t = 1 we get,

A = 4000 (1+\frac{22}{100} )^{1}

or, A = 4880

Again,

b) Taking, P = 4000, r = 22 and t = 4 w eget,

A = 4000(1+\frac{22}{100})^{4}

or, A = 7263.39

Hence,

a) The amount of loan after 1 year is $ 4880

and b) The amount of loan after 4 year is $ 7263.39.

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How many times greater is the vuale in 4 in 547 than 4 in 84
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Answer:

10 times

Step-by-step explanation:

4 in 547 is equal to 40

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When you separate that number into smaller parts

Ex: 547 = 500 + 40 + 7

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What are the multiples of 4 and 6?
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Answer:

Step-by-step explanation:

For example, to find the common (positive) multiples of 4 and 6, we might list: Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, … Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, … The numbers 12, 24, 36, and 48 appear on both of these lists, and more would appear if the lists were longer.

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Multiply and simplify. 2x4yx⋅6xy2z3
OLEGan [10]

Answer:

The given expression 2x^4yx \times 6xy^2z^3   on multiplying  is 12x^6y^3z^3

Step-by-step explanation:

Consider the given two expressions 2x^4yx and 6xy^2z^3

We have multiply both expressions,

2x^4yx \times 6xy^2z^3

To multiply two terms first multiply constant numbers that is 6 × 2 = 12

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x^a\cdot x^b=x^{a+b}

Then power of x together will be,

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Similarly for y powers,

y \cdot y^2=y^{1+2}=y^3

Since first term do not have any expression for z so it will remain same.

Thus, the given expression  on multiplying become,

2x^4yx \times 6xy^2z^3 is 12x^6y^3z^3




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