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Strike441 [17]
3 years ago
7

There are 4 red marbles and 2 blue marbles in a bag. What is the least number of red and blue marbles that can be added to the b

ag to create a ratio of 3 red marbles to 1 blue marble
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

3 + 1 = 4

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Solving inequalities unit portfolio algebra 1a (ASAP) please
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Answer:

berpengalamanfundamentalisme nya codot chihuahua Kukuh

5 0
3 years ago
What is the value of b2 - 4ac for the following equation?<br><br> 2x 2 - 2x - 1 = 0
NikAS [45]
2x^2-2x-1=0
\Delta=b^2-4ac

\Delta=(-2)^2-4*2*(-1)=4+8=12
5 0
3 years ago
Read 2 more answers
Three marbles are selected from an urn con- taining 5 red marbles and 3 green marbles. After the number X of red marbles is reco
maw [93]

Answer:

explanation has been shown in the attachments.

Step-by-step explanation:

7 0
3 years ago
A high school runs a survey asking students if they participate in sports. The results are found below. Run an independence test
Sveta_85 [38]

Answer:

It can be concluded that participation in sports is dependent on grade level.

Step-by-step explanation:

In this case a Chi-square independence test for the data is to be performed at <em>α </em>= 0.01.

The hypothesis can be defined as follows:

H₀: The participation in sports is independent of grade level.

<em>Hₐ</em>: The participation in sports is dependent of grade level.

The data provided is:

            Freshmen      Sophomores       Juniors         Seniors

Yes            75                       88                   55                42

No             30                      28                   38                 40

The formula to compute the expected frequencies is:

E_{i}=\frac{i^{th}\ \text{Row Total}\ \times\ i^{th}\ \text{Column Total}}{N}

The Chi-square statistic is:

\chi^{2}=\sum {\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

Consider the Excel file attached below.

The value of Chi-square statistic is 16.244.

The degrees of freedom of the test are:

\text{df}=(r-1)(c-1)

    =(4-1)(2-1)\\=3\times 1\\=3

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{df}

                =P(\chi^{2}_{3}

*Use a Chi-square table.

<em>p</em>-value = 0.001 < <em>α</em> = 0.01

The null hypothesis will be rejected at 1% level of significance.

Thus, it can be concluded that participation in sports is dependent on grade level.

4 0
4 years ago
What’s the area and the circumference of a circle with diameter 8m?
MatroZZZ [7]

Answer:

50.24

Step-by-step explanation:

8÷2 is the radius. 3.14×4^2=50.24 m^2

^= where the exponent is supposed to go

8 0
3 years ago
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