3 years ago

Someone please help me with this

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

4 0

V = (1/3) B * h
B = area of the base
V = (1/3) * 900 * 40
V = 12,000 m^3

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A projectile fired at 5 m/s from a gun. If the horizontal component of the initial velocity is equal to 4 m/s. What is the value

svlad2 [7]

Answer:

$the \: value \: of \: the \: vertical \: component \to : \\ (v_v) = 3m {s}^{ - 1} \\$

Step-by-step explanation:

$let \: the \: velocity \: be \to \: v \\let \: the \: horizontal \: component \: be \to \: v_h \\ let \: the \: vertical \: component \: be \to \: v_v \\ applying \: the \: pythagorean \: rule \: of \: vectors \to : \\ {v}^{2} = {v_v}^{2} + {v_h}^{2} \\ {v_v}^{2} = {v}^{2} - {v_h}^{2} \\ {v_v}^{2} = {5}^{2} - {4}^{2} \\ v_v = \sqrt{(25 - 16)} \\ v_v = \sqrt{9} \\ \boxed{ v_v = 3 {ms}^{ - 1} }$