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3 years ago

3. One of the graphs represents

Mathematics

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

3x-2y=6

Step-by-step explanation:

Subtract 3x from both sides of the equation

Divide each term by −2 and simplify.

y=-3+ $\frac{3x}{2}$

Rewrite in slope-intercept form

y= $\frac{3}{2} *-3$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of m and b using the form y=mx+b

$m=\frac{3}{2}$

$b=-3$

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: $\frac{3}{2}$

y-intercept: -3

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values.

Choose 0 to substitute in for x to find the ordered pair.

(0,−3)

Choose 1 to substitute in for x to find the ordered pair.

$(1,-\frac{3}{2} )$

Graph the line using the slope and the y-intercept, or the points.

slope: $\frac{3}{2}$

y-intercept:-3

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Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

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Elanso [62]

The margin of error given the proportion can be found using the formula

$z* \sqrt{ \frac{p(1-p)}{n} }$

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$n$ is the sample size

We have
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$p=0.38$
$n=80$

Plugging these values into the formula, we have:
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The result 0.14 as percentage is 14%

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