What is the total area of a cylinder that has a radius of 5 cm and a height of 12 cm

What is the justification for each step in solving the inequality?<br><br> −7(3+8x)+5x≤1−62x

dangina [55]

Distribute -7 because of math
-21-56x+5x≤1-62x
add like terms because you aint chaingin nothing
-21-51x≤1-62x
add 62x to both sides (addition property of equality, where a=a and b=b, a+b=a+b) and also (addative inverse, a+(-a)=0) that turns the -62x to 0
-21+11x≤1
add 21 to both sides (additiona proerty of equality and addativeinverse)
11x≤22
divide both sides by 11 (division property of equality, if a=a and b=b, then a/b=a/b)
x≤2

5 0

3 years ago

Read 2 more answers

The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$

4 0

3 years ago

Help asap pleeassseeeee!!!

natali 33 [55]

Volume of oblique cylinder
= (base area) * height (perpendicular to base)
= (30 π )*m
= 30m π cm^3

6 0

2 years ago

If a stadium pays $11000 for labor and $7000 for parking what would the stadiums parking revenue be if the stadium is hoping par

Alchen [17]

Answer:

$300,000

Step-by-step explanation:

Labor cost = $11,000

Parking cost= $7,000

Parking Labor cost = $ 18,000

Parking Revenue = ?

From the question, parking labor cost is 6% of Parking revenue.

6% = Parking Labor cost/ Parking Revenue------------------------------------ (1)

Further substituting in (1) gives:

6/100 = 18,000/ Parking Revenue

Making Parking Revenue the subject of the formula, we have:

Parking Revenue = (100 x 18,000)/6

= $300,000

4 0

3 years ago

Find the coordinate of point P that lies along the directed line segment from A (3, 4) to B (6, 10) and partitions the segment i

AveGali [126]

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
A(3,4)\qquad B(6,10)\qquad
\qquad 3:2
\\\\\\
\cfrac{AP}{PB} = \cfrac{3}{2}\implies \cfrac{A}{B} = \cfrac{3}{2}\implies 2A=3B\implies 2(3,4)=3(6,10)\\\\
-------------------------------\\\\
{ P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\\
-------------------------------$

$\bf P=\left(\cfrac{(2\cdot 3)+(3\cdot 6)}{3+2}\quad ,\quad \cfrac{(2\cdot 4)+(3\cdot 10)}{3+2}\right)
\\\\\\
P=\left( \cfrac{6+18}{5}~~,~~\cfrac{8+30}{5} \right)\implies \left( \cfrac{24}{5}~~,~~\cfrac{38}{5} \right)\implies \left( 4\frac{4}{5}~~,~~7\frac{3}{5} \right)$

8 0

3 years ago