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Yuki888 [10]
3 years ago
9

A church building fund has invested some money in two ways: part of the money at 7% interest and four times as much at 11%. Find

the amount invested at each rate if the total annual income from interest is 7650.
Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer: he invested $15000 in part 1 and $60000 in part 2

Step-by-step explanation:

Let x represent the amount of money invested in part one.

Let 4x represent the amount of money invested in part 2 .

Total amount of money invested in part 1 and part 2 is

x + 4x = 5x

The formula for simple interest is expressed as

I = PRT/100

Where

P is the principal or initial amount.

T is the duration in years

R is the number rate.

For part 1

R = 7%

T = 1 year

P = x

I = (x × 7 × 1)/100 = 0.07x

For part 2,

R = 11%

T = 1 year

P = 4x

I = (4x × 11 × 1)/100 = 0.44x

if the total annual income from interest is 7650. This means that

0.44x + 0.07x = 7650 - - - - - - - -2

0.51x = 7650

x = 7650/0.51

x = 15000

Amount invested in part 1 is $15000

Amount invested in part 2 is 4×15000 = $60000

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<h3>What is an Expression ?</h3>

An expression is a mathematical statement consisting of variables , constant and mathematical operators.

The expression given is

(x+1)(x+2)(x+3)(x+4)+2019

To find the minimum value

(x+1)(x+2) = ( x² +3x +2) = ( x +5/2)² - 9/4

(x+3)(x+4) =  (x² +7x +12) = ( x +5/2)² -1/4

(x+1)(x+2)(x+3)(x+4) = (  x +5/2)⁴ - 5/2 ( x +5/2)² +9/16

Considering ( x +5/2)²  = y

(x+1)(x+2)(x+3)(x+4) = y² - 5/2y + 9/16

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The minimum value when x is a real number is -1

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x has two possible real solution

and the least possible value of (x+1)(x+2)(x+3)(x+4)+2019 where x is a real number is 2018.

To know more about Expression

brainly.com/question/14083225

#SPJ1

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