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Alexandra [31]
3 years ago
8

An ant weighs 2 x 10^-3 grams, and a lion weighs 1 x 10^5. The lion's weight is 5 x 10^x times greater than the ant's weight. Wh

at is the value of x?
x = ?
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

x=7

Step-by-step explanation:

Information provided

Weight of ant=2*10^{-3} grams

Weight of lion=1*10^{5} but units are not provided, assuming this unit is also grams

How many times lion's weight exceed an ant

\frac {1*10^{5}}{2*10^{-3}}=50000000

=5*10^{7}

Therefore, the value of x=7 if the unit for weight of lion is assumed to be same as unit for weight of an ant

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Please help me with my Algebra homework!!!
balu736 [363]

Answer:

B) No Unique Solutions

Step-by-step explanation:

Given:

z=x+5y-14

-2y=-4\\y={-4}{-2}=2

3x+y-3z=14

now we now the value of y = 2 so we will substitute in equation  z=x+5y-14

z=x+5\times2-14\\z=x+10-14\\z= x-4

Now, We have value of y=2 and value of z=x-4 Substituting in both the value in equation 3x+y-3z=14

3x+2-3(x-4)=14\\3x+2-3x+12=14\\14=14

which means that the equation has Infinite solutions.

7 0
3 years ago
Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote
Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

\frac{x(2x - 3)}{(x + 2)x}

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

\frac{2x - 3}{x + 2}

We don't want the denomiator be zero because we can't divide by zero.

so

x + 2 = 0

x =  - 2

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

\frac{2}{1}  = 2

So we have a horinzontal asymptofe of 2

7 0
3 years ago
Petra jogs 5 miles in 40 minutes. At this rate, how long would it take her to jog 7 miles?
Wittaler [7]
(40 min)/(5 mi) = (time)/(7 mi) . . . . . the rates are the same
(7/5)*(40 min) = time = 56 min

At the same rate, it would take Petra 56 minutes to jog 7 miles.
6 0
4 years ago
Read 2 more answers
Alyssa is factoring the following expression p∆2-8p-9. She said the answer is (p-1) (p +9). Is she correct? If not, explain her
Lesechka [4]

Answer:

Step-by-step explanation:

p^2-8p-9

factor out the trinomial

(p-9)(p+1)

Therefore, she's incorrect. Because (p-1)(p+9)=p^2-p+9p-9=p^2+8p-9 and that's different from p^2-8p-9.

5 0
3 years ago
My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits. Write the 2-digit number that match
pochemuha

Answer:

The number is 91

Step-by-step explanation:

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∵ 0 is not the digit of the number,

Hence, y = 9 and x = 1

Therefore, required number = 10(9) + 1 = 90 + 1 = 91

6 0
3 years ago
Read 2 more answers
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