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aleksklad [387]
3 years ago
5

Find the equation of the line passing through the points (5, 2) and (10, 6). y = Xt

Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

y=4/5x-2

Step-by-step explanation:

here are the given points: (5,2) and (10,6)

First, let's find the slope, which is found with the equation (y2-y1)/(x2-x1)

so let's label the points

x1=5

y1=2

x2=10

y2=6

now we can substitute into the equation

m=(6-2)/(10-5)

subtract

m=4/5

so that means the slope is 4/5

Now, let's use point slope form, which is y-y1=m(x-x1) (m is the slope)

so let's substitute the numbers we know from earlier into the equation

y-2=4/5(x-5)

do distributive prop.

y-2=4/5x-4

add 2 to both sides

y=4/5x-2

hope this helps!

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Answer:

\{\sqrt b, -\sqrt b\}

Step-by-step explanation:

Given

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Split:

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Option A

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Given:

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The standard form of equation of circle with center and radius is:

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x^2+y^2-6x-16y+48=0

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