Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
Step one: divide both sides by -2.3 to get X by itself: X=-.2. :)
Answer:
The second one.
Step-by-step explanation:
Answer:
1/2
Step-by-step explanation:
just count graph it will give I 1/3
Answer:
Maximum height is 7 feet
Step-by-step explanation:
Solution:-
- The complete question is as follows:
" The height of a small rise in a roller coaster track is modeled by f(x) = –0.07x^2 + 0.42x + 6.37, where x is the distance in feet from a supported at ground level.
Find the greatest height of the rise "
- To find any turning points ( minimum or maximum ) points of a trajectory expressed as function of independent parameter, we find the critical points of the trajectory where the first derivative of the dependent variable w.rt independent variable is set to zero.
- In our case the height of the roller coaster track (y) is function of the distance (x) from a supported pole at ground level.
f(x) = –0.07x^2 + 0.42x + 6.37
- Now set the first derivative equal to zero, and determine the critical values of x:
0 = -0.14x + 0.42
x = 0.42 / 0.14 = 3 ft
- The critical value for the coaster track is at point 3 feet away from the supported pole at ground level. So the height f(x) at x = 3 ft, would be:
f ( x = 3 ) = max height
max height = –0.07*3^2 + 0.42*3 + 6.37
= 7 ft
