To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer: x is grater or equal to -18
Inter el notation
[-18,oo)
Step-by-step explanation:
Answer:
length=4
width=30
Step-by-step explanation:
length=x
width=8x-2
(8x-2)*2+2x=68
16x-4+2x=68
18x=72
x=4 (Length)
4*8=32, 32-2=30(width)
Answer:
x= -10
Step-by-step explanation:
................
51,007.
If you want it is thousandths,
7.051.
Bye!
