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3 years ago

Explain how to determine the x- and y- intercepts of a line from a given equation in y = mx + b form.

Mathematics

1 answer:

NISA [10]3 years ago

3 0

Answer:

Step-by-step explanation:

x-intercept: Set y = 0 and solve for x:

0 = mx + b, or mx = -b, or x = -b/m. x-intercept is then (-b/m, 0)

y-intercept: Set x = 0 and solve for y: y = m(0) + b, or y = b. y-intercept is then

(0, b).

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Can someone solve -192= -6 (6x - 4) step by step?

olasank [31]

Answer:

x= 4 2/3 OR 14/3 OR 4.6... –– 4 2/3 and 4.6... are the simplest form.

Step-by-step explanation:

Your original equation is -192 = -6 (6x - 4):

1. -192 = -6 (6x - 4)

Use distributive property and multiply: -6 x 6x = -36x and -6 x -4 = 24:

2. -192 = -36x + 24

We now move the +24 onto the other side of the equation, -192. Add 24 onto -192 and since we're moving the 24 on the left side of the equation, 24 will removed, so -24 on the right side of the equation:

3. -192 + 24 = -36x + 24 - 24

Divide both sides of the equations by -36 to get "x" by itself:

4. -168 / -36 = -36x / -36

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3 years ago