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sleet_krkn [62]
2 years ago
14

(x2y-3y2+5xy2)-(-x2y+3xy2-3y2)

Mathematics
1 answer:
Reil [10]2 years ago
8 0
2x2y+8xy2-6y2 .........
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The next number in the series of intervals of 38, 36,30,28,22,is=
Ivenika [448]
There is a pattern of -2, -6, so the next number is 20.
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3 years ago
Please help!! :(((((((
masha68 [24]
The answers would be 11, if you plug it in it would be 5(11)-7=48
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Help Me With These Please
Gwar [14]
Look up the formula to find the area of a trapezoid. Then do the math HINT: The formula is 

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3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
If a and b are positive numbers, find the maximum value of f(x) = xa(7 â x)b on the interval 0 ⤠x ⤠7.
algol [13]
Given f(x)=x^a(7-x)^b on the interval 0 ≤ x ≤ 7, for maximum value, f'(x) = 0.

f'(x)=0 \\  \\ \Rightarrow -bx^{a}(7-x)^{b-1}+ax^{a-1}(7-x)^b=0 \\  \\ \Rightarrow ax^{a-1}(7-x)^b=bx^{a}(7-x)^{b-1} \\  \\ \Rightarrow a(7-x)=bx \\  \\ \Rightarrow (a+b)x=7a \\  \\ \Rightarrow x= \frac{7a}{a+b}
8 0
3 years ago
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