(x2y-3y2+5xy2)-(-x2y+3xy2-3y2)

Expand (x-2) (x-1). Must be in polynomial form.

Ludmilka [50]

To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = $x^{2}$

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

(-2)*(-1) = 2

Now that we have our four terms, let us add them together and combine like terms:

$x^{2} + (-x) + (-2x) + 2$

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

-x + (-2x) = -3x

So now that we have our terms completed, we can combine into one polynomial equation:

$x^{2} + (-3x) + 2$ or $x^{2} -3x+2$

6 0

3 years ago

What must be true of PQ?

yulyashka [42]

Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong.

PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.

PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.

The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable).

8 0

3 years ago

Frankie the frog stands at the number 0 on a number line and wants to hop to the number 8. he can hop 1, 2, 3 units forward in a

ycow [4]

In order to hop 8 units, you can do:

1 two-units hops, 2 three-units hops

4 two-units hops

1 one-unit hops, 2 two-units hops, 1 three-units hops

2 one-unit hops, 2 three-units hops

2 one-unit hops, 3 two-units hops

3 one-unit hops, 1 two-units hops, 1 three-units hops

4 one-unit hops, 2 two-units hops

5 one-unit hops, 1 three-units hops

6 one-unit hops, 1 two-units hops

8 one-unit hops

7 0

3 years ago

Can you please help me on add and subtract fractions level 1 9/8-11/8

zhannawk [14.2K]

Answer:

7/8

Step-by-step explanation:

1. Make 1 9/8 into an improper fraction

1 = 8/8

8/8 + 9/8 = 17/8

2. Subtract

17/8 - 11/8 = 7/8

3 0

3 years ago

Read 2 more answers

What is the gcf for 14 and 55?

pentagon [3]

The greatest common factor would be 1 because you need to factor both 14 and 55 so factor 14 and you get 2 and 7 factor 55 you get 5 and 11 the the GCF has to be 1
I hope this is helpful

4 0

3 years ago