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Allushta [10]
3 years ago
7

Expand (x-2) (x-1). Must be in polynomial form.

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0
To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = x^{2}

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

(-2)*(-1) = 2

Now that we have our four terms, let us add them together and combine like terms:

x^{2}  + (-x) + (-2x) + 2

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

-x + (-2x) = -3x

So now that we have our terms completed, we can combine into one polynomial equation:

x^{2} + (-3x) + 2 or x^{2} -3x+2
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Find the ordered pair that makes both the equations below true
NNADVOKAT [17]

Answer:

(3, 1)

Step-by-step explanation:

(a) Algebraic solution

(1)  y = -⅔x + 3

(2) y =   2x  - 5

Set Equation (1) equal to Equation (2)

-⅔x + 3 = 2x - 5

Multiply each side by 3

-2x + 9 = 6x - 15

Add 15 to each side

-2x + 24 = 6x

Add 2x to each side

24 = 8x

Divide each side by 3

(3) x = 3

Substitute (3) into (2)

y = 2×3 - 5 = 6 - 5 = 1

The ordered pair that makes both equations true is (3, 1).

(b) Graphical solution

In the diagram below, the red line is the graph of Equation (1). The blue line is the graph of Equation (2). The point of intersection is at (3, 1).

7 0
3 years ago
Help plz..........................................................................................
Zarrin [17]
The answer is the last one
3 0
3 years ago
Read 2 more answers
FIRST ANSWER GET BRAINLEST
liraira [26]

Let's call x the price of a box of slime.

Gianna spent 4 × $58 for art supplies so 4(58) + 8x all together.  We have

392 ≤  4(58) + 8x ≤ 472

We can work with both inequalities at once.  4(58)=232 so we subtract that from all three sides.

160 ≤ 8x ≤ 240

Divide all three sides by 8, a positive number so the inequalities don't flip.

20 ≤ x ≤ 30

Answer: Least: $20, Most: $30


5 0
3 years ago
Read 2 more answers
In ΔTUV, the measure of ∠V=90°, UT = 65, VU = 56, and TV = 33. What ratio represents the cosine of ∠T?
monitta

<u>Answer:</u> The ratio that represents the cosine of ∠T is \frac{56}{65}

<u>Step-by-step explanation:</u>

We are given:

UV = 56 units

VT = 33 units

UT = 65 units

∠V = 90°

Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

\cos \theta=\frac{\text{base}}{\text{hypotenuse}}

Base of the triangle is UV and the hypotenuse of the triangle is TU

Putting values in above equation, we get:

\cos \theta=\frac{UV}{TU}=\frac{56}{65}

Hence, the ratio that represents the cosine of ∠T is \frac{56}{65}

6 0
2 years ago
Which angle is the included angle for JL and KL ?<br> A) L<br> B) K<br> C) L
umka2103 [35]
<span>angle for JL and KL is <L
answer is C. L</span>
6 0
3 years ago
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