Shawn found that a solution of x = 3 was extraneous for his function. What would be a possible denominator in Shawn's function?
2 answers:
Answer:
Option B is correct
Step-by-step explanation:
Given: A solution x =3 was extraneous for his function.
Extraneous solution defined as a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.
The only function from the given options
f(x) = has the solution x =3
therefore,
3 is excluded from the domain of the because it would make the denominator of one of the fractions zero and division by zero is not allowed.
Therefore, it cannot be a root of the equation
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Answer:
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Step-by-step explanation:
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Answer:
2x + 3y ≥ 5
Step-by-step explanation:
See the graph attached.
The bold straight line passes through the points (1,1) and (4,-1).
Therefore, the equation of the straight line will be
⇒ 3(y + 1) = - 2(x - 4)
⇒ 3y + 3 = - 2x + 8
⇒ 2x + 3y = 5 ............. (1)
Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).
So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5
Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)