Question

Shawn found that a solution of x = 3 was extraneous for his function. What would be a possible denominator in Shawn's function?

Answer 1

Your answer is B. x2 -2x -3

Hope this helps!!

Answer 2

Answer:

Option B is correct

Step-by-step explanation:

Given: A solution x =3 was extraneous for his function.

Extraneous solution defined as a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

The only function from the given options

f(x) = $x^2-2x-3$ has the solution x =3

therefore,

3 is excluded from the domain of the $\frac{x^2-2x-3}{x-3}$  because it would make the denominator of one of the fractions zero and division by zero is not allowed.

Therefore, it cannot be a root of the equation $\frac{x^2-2x-3}{x-3}$