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3 years ago

ABC is reflected over the y-axis

Mathematics

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

A'(-1, 5), B'(-2, 3), and C'(-5, 4)

Step-by-step explanation:

Given the coordinate (x, y), if reflected over the y-axis, the resulting coordinate will be (-x, y):

Given the coordinates of the triangle expressed as:

A(1. 5), B(2, 3), and C(5, 4)

When these coordinates are reflected over the y-axis, the results will be:

A'(-1, 5), B'(-2, 3), and C'(-5, 4)

<em>Note that the x coordinates were negated while the y-coordinates remains unchanged</em>

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The sum of two polynomials is 8d^5-3c^3d^2+5c^2d^3-4CD^4+9. If one added is 2d^5-c^3d^4+8CD^4+1, what is the other added

insens350 [35]

Answer:

6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8

Step-by-step explanation:

We need to subtract the given polynomial from the sum:-

8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^4 + 8cd^4 +1 )

We need to distribute the negative over the parentheses:-

= 8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - 2d^5 + c^3d^4 - 8cd^4 -1

Bringing like terms together:

= 8d^5 - 2d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 4cd^4 - 8cd^4 + 9

- 1

Simplifying like terms

= 6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8

8 0

3 years ago

Plz i need help i don't understand it

andreev551 [17]

Answer:

y=5,2 and -3

we have to put the values of X and then solve the equation.

5 0

3 years ago

Read 2 more answers

the ratio of the shoes sold to sndals sold was 3:10 if there were 14 more sandalssoldhow many shoes weresold?

Dafna11 [192]

The ratio would be 8:24 (Shoes sold is 8)

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3 years ago

The distance between city A and B is 600 km. The first train left A and headed towards B at the speed of 60 km/hour. The secon

hoa [83]

$\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
A&d&60&t\\
B&600-d&v&t+3
\end{array}$

$\bf \textit{meaning}\implies 
\begin{cases}
d=(60)(t)
\\ \quad \\
600-d=(v)(t+3)\\
------------\\
d=\boxed{60t}\qquad thus
\\ \quad \\
600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"}
\end{cases}$

keep in mind, that "t" is the time when the train at A station, left towards B station

they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference

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3 years ago

Find the rate of change between (-3,6) (0,-3)

marin [14]

<h3>The rate of change between (-3,6) (0,-3) is -3</h3>

<em><u>Solution:</u></em>

Given that,

We have to find the rate of change between (-3,6) (0,-3)

<em><u>The rate of change is given as:</u></em>

$Rate\ of\ change = \frac{y_2-y_1}{x_2-x_1}$