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2 years ago

ABC is reflected over the y-axis

Mathematics

1 answer:

uranmaximum [27]2 years ago

8 0

Answer:

A'(-1, 5), B'(-2, 3), and C'(-5, 4)

Step-by-step explanation:

Given the coordinate (x, y), if reflected over the y-axis, the resulting coordinate will be (-x, y):

Given the coordinates of the triangle expressed as:

A(1. 5), B(2, 3), and C(5, 4)

When these coordinates are reflected over the y-axis, the results will be:

A'(-1, 5), B'(-2, 3), and C'(-5, 4)

<em>Note that the x coordinates were negated while the y-coordinates remains unchanged</em>

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What is number in unit form

Mazyrski [523]

What are the answer choices can you attach a pic?

5 0

2 years ago

In the pediatric unit of a hospital has 165 beds how many are there if each room holds 3 beds

andrew-mc [135]

Answer:

There are 55 rooms

Step-by-step explanation:

There are 165 beds in the hospital. Each room contains 3 beds. In order to find the number of beds per room, take the total number of beds and divide it by the number of rooms in each bed. 165/3=55. There are 55 rooms in the hospital, all containing 3 beds.

Hope this helps!

8 0

2 years ago

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

2 years ago

Can someone please help me with this? I'll give brainliest :)

vlabodo [156]

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

<h3>How to determine the slope?</h3>

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

$m = \frac{y_2 -y_1}{x_2-x_1}$

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

$m = \frac{11 - 2}{5 - 2}$

$m = \frac{9}{3}$

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

$m = \frac{28 + 2}{5 - 2}$

$m = \frac{30}{3}$

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10