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4 years ago

PLEASE ANSWERRRRRRRRRRRRRRRRRR

Mathematics

1 answer:

MArishka [77]4 years ago

5 0

Answer:

B . 1500 children and 700 adults

Step-by-step explanation:

<h2><u>How many children and how many adults attended?</u></h2>

create an equation

make use of variables:

children --x

adults --y

1.5x + 4y = 5050

x + y = 2200

<u><em>now make use of the options given and place them into the equation .</em></u>

lets try the first one

1.5 * (700) + 4*(1500) = 7050

<h3>HENCE : A IS WRONG </h3>

lets try the second one

1.5 * ( 1500) + 4 *(700) = 5050

<h3>HENCE : B IS CORRECT..</h3>

<u>the answer is B.</u>

you can check the others if you want to , so that you are able to see if you are correct. ( optional)

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3 years ago

ticket sales for a local concert totaled $101,244 yesterday. After the ticket window closed today, the cashiers counted 968 tick

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2 years ago

Suppose that you live in a community that has 125,000 households. Among these households, 50,000 have traditional landline telep

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Answer:

0.4 = 40% probability that the second household selected will have a traditional landline telephone

Step-by-step explanation:

A probability is given by the number of desired outcomes divided by the number of total outcomes.

We have that:

125,000 households

50,000 have traditional landlines telephones.

The first household selected does not have a traditional landline telephone.

Now we have 125000 - 1 = 124,999 households, and 50,000 have traditional landlines telephones.

What is the probability that the second household selected will have a traditional landline telephone

$p = \frac{50000}{124999} = 0.4$

0.4 = 40% probability that the second household selected will have a traditional landline telephone

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3 years ago

Which relations are functions?

mart [117]

Answer:

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4 years ago

Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like

blsea [12.9K]

Answer:

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

(a) You like both of them.

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{2}{14} = 0.029$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{11}{14} = 0.629$

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343$

(d) Redo (a)-(c) if a song can be replayed before all

(a) You like both of them. Would this be unusual?

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{3}{15} = 0.04$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{12}{15} = 0.64$

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4 years ago