Answer:
b) Determine the heat transfer into the cycle and the net work for the cycle, in kJ.
Explanation:
Answer:
true
Explanation:
the answer is true because if u don't have a valid license when operating a vehicle and you get pulled over you will get in trouble i know this because my parents got in trouble for it once
Answer:
The coefficient of linear expansion of the metal is ∝ = 2.91 x 10⁻⁵ °C⁻¹.
Explanation:
We know that Linear thermal expansion is represented by the following equation
Δ L = L x ∝ x Δ T ---- (1)
where Δ L is the change in length, L is for length, ∝ is the coefficient of linear expression and Δ T is the change in temperature.
Given that:
L = 0.6 m
T₁ = 15° C
T₂ = 37° C
Δ L = 0.28 mm
∝ = ?
Solution:
We know that Δ T = T₂ ₋ T₁
Putting the values of T₁ and T₂ in above equation, we get
Δ T = 37 - 15
Δ T = 22 °C
Also Δ L = 0.28 mm
Converting the mm to m
Δ L = 0.00028 m
Putting the values of Δ T, Δ L, L in equation 1, we get
0.00028 = 0.6 x ∝ x 22
Rearranging the equation, we get
∝ = 0.00028 / (0.6 x 16)
∝ = 0.00028 / 13.2
∝ = 2.12 x 10⁻⁵ °C⁻¹
Answer:
The answer is 960 kg
Explanation:
Solution
Given that:
Assume the initial dye concentration as A₀
We write the expression for the dye concentration for one hour as follows:
ln (C₁) = ln (A₀) -kt
Here
C₁ = is the concentration at 1 hour
t =time
Now
Substitute 480 g for C₁ and 1 hour for t
ln (480) = ln (A₀) -k(1) ------- (1)
6.173786 = ln (A₀) -k
Now
We write the expression for the dye concentration for three hours as follows:
ln (C₃) = ln (A₀) -k
Here
C₃ = is the concentration at 3 hour
t =time
Thus
Substitute 480 g for C₃ and 3 hour for t
ln (120) = ln (A₀) -k(3) ------- (2)
4.787492 = ln (A₀) -3k
Solve for the equation 1 and 2
k =0.693
Now
Calculate the amount of blue present initially using the expression:
Substitute 0.693 for k in equation (2)
4.787492 = ln (A₀) -3 (0.693)
ln (A₀) =6.866492
A₀ =e^6.866492
= 960 kg
Therefore, the amount of the blue dye present from the beginning is 960 kg
Answer:
- B. Precipitation require the diffusional activation energy plus an additional energy to form the precipitate.
Explanation:
Precipitation is the creation of a solid from a solution. When the reaction occurs in a liquid solution, the solid formed is called the precipitate.
The formation of a precipitate indicates the occurrence of a chemical reaction.
Precipitation of carbide requires alot of energy which the diffusion activational energy alone cannot achieve and this was calculated to be 225.6 kJ/mol.