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3 years ago

The criminal and traffic code requires that a driver must have a valid driver's license in his/her

Engineering

1 answer:

ankoles [38]3 years ago

5 0

Answer:

true

Explanation:

the answer is true because if u don't have a valid license when operating a vehicle and you get pulled over you will get in trouble i know this because my parents got in trouble for it once

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Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and evens (like the 10 or 90)

IrinaVladis [17]

Answer:

#include <iostream>

using namespace std;

int main()

{

int inputNumber ;

cout << "Enter an interstate highway number:";

cin >> inputNumber ;

if(inputNumber<=0 || inputNumber >= 1000)

cout << inputNumber << " is not a valid interstate highway number" << endl ;

else{

if(inputNumber > 99){

cout << "I-"<<inputNumber<< " is auxiliary, ";

int temp = inputNumber % 100 ;

cout <<"serving I-"<<temp<<", ";

if(temp%2==0){

cout << "going east/west." << endl;

}

else{

cout << "going north/south." << endl;

}

else{

cout << "I-"<<inputNumber<< " is primary, ";

if(inputNumber%2==0){

cout << "going east/west." << endl;

}

else{

cout << "going north/south." << endl;

}

return 0;

}

Explanation:

Check if input number is greater than 99, then display that the input number is auxiliary.
Check if remainder of input number/2 is equal to 0, then display that going east/west.

3 0

3 years ago

An air conditioner operating at steady state maintains a dwelling at 70°F on a day when the outside temperature is 99°F. The rat

IrinaVladis [17]

Answer:

a) the coefficient of performance of the air conditioner is 3.5729

- the power input required for a reversible air conditioner is 0.645 hp

- the coefficient of performance for the reversible air conditioner is 18.2759

Explanation:

Given the data in the question;

Lower Temperature $T_L$ = 70°F = ( 70 + 460 )R = 530 R

Higher Temperature $T_H$ = 99° F = ( 99 + 460 )R = 559 R

Cooling Load $Q_L$ = 30000 Btu/h

we know that 1 hp = 2544.43 Btu/h

Net power input P = 3.3 hp = ( 3.3 × 2544.43 )Btu/h = 8396.619 Btu/h

Coefficient of performance of the air conditioner;

$COP_{air-condition$ = Cooling Load $Q_L$ / power P

we substitute

$COP_{air-condition$ = 30000 Btu/h / 8396.619 Btu/h

$COP_{air-condition$ = 3.5729

Therefore, the coefficient of performance of the air conditioner is 3.5729

- Power input required ( in hp )

$Q_L$ / $P_{required$ = $T_L$ / ( $T_H$ - $T_L$ )

we substitute

30000 Btu/h / $P_{required$ = 530 R / ( 559 R - 530 R )

30000 Btu/h / $P_{required$ = 530 R / 29 R

we solve for $P_{required$

$P_{required$ = ( 30000 Btu/h × 29 R ) / 530 R

$P_{required$ = ( 870000 Btu/h / 530 )

$P_{required$ = 1641.5094 Btu/h

we know that; 1 hp = 2544.43 Btu/h

so;

$P_{required$ = ( 1641.5094 / 2544.43 ) hp

$P_{required$ = 0.645 hp

Hence, the power input required for a reversible air conditioner is 0.645 hp

- the coefficient of performance for the reversible air conditioner;

$COP_{rev-air-condition$ = $T_L$ / ( $T_H$ - $T_L$ )

we substitute

$COP_{rev-air-condition$ = 530 R / ( 559 R - 530 R )

$COP_{rev-air-condition$ = 530 R / 29 R

$COP_{rev-air-condition$ = 18.2759

Hence, the coefficient of performance for the reversible air conditioner is 18.2759

3 0

3 years ago

If f(

EastWind [94]

Can you retype this in for me so I can do it cause it’s lined up instead of horizontal

8 0

3 years ago

Which excerpt from "The Chrysanthemums' best reveals that Elisa is proud of her

Alisiya [41]

Scissors to avoid any rough edges

4 0

3 years ago

Shear plane angle and shear strain: In an orthogonal cutting operation, the tool has a rake angle = 16°. The chip thickness befo

Oduvanchick [21]

Answer:

shear plane angle Ф = 26.28°

shear strain 2.20

Explanation:

given data

angle = 16°

chip thickness t1 = 0.32 mm

cut yields chip thickness t2 = 0.72 mm

solution

we get here first chip thickness ratio that is

chip thickness ratio = $\frac{t1}{t2}$ ................. 1

put here value

chip thickness ratio = $\frac{0.32}{0.72}$

chip thickness ratio r = 0.45

so here shear angle will be Ф

tan Ф = $\frac{r*cos\alpha }{1-rsin\alpha}$ ............2

tan Ф = $\frac{0.45*cos16 }{1-rsin16}$

tan Ф = 0.4938

Ф = 26.28°

and

now we get shear strain that is

shear strain r = cot Ф + tan (Ф - α ) ................3

shear strain r = cot(26.28) + tan (26.28 - 16 )

shear strain r = 2.20

6 0

3 years ago