The criminal and traffic code requires that a driver must have a valid driver's license in his/her
1 answer:
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Answer:
4.536hp
Explanation:
The decrease in the heat gain of the room is determined from difference in electrical inputs:
The question is incomplete. The complete question is :
The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .
When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?
Solution :
Given data :
Diameter of the rod : 46 mm
Torque, T = 85 Nm
The polar moment of inertia of the shaft is given by :
J = 207.6
So the shear stress at point A is :
Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.
Answer:
porosity=23.07%
x=5.974*10^9cm^3
Explanation:
One liter of oven-dry soil sampled from the Chorro Creek Ranch field requires 300 g of water to completely saturate it.
Calculate (a) its porosity, n, and (b) the volume of water required to saturate the top 20 cm of 1 hectare of the field.
-Porosity of a soil sample can be calculated in five ways but i shall use the formula below
porosity=%
volume pore volume of sample is equal to water volume used to saturate the soil
total volume=sample volume +pore volume
1L=1000cm^3
density of water=density=mass/volume
1g/cm^3=300g/volume
vol=300cm^3
total volume=300+1000
1300
porosity =(300/1300)*100%
porosity=23.07%
2. Recall that volume=area *height
1 hectare=1*10^9cm^2
the volume of soil sample=1*10^9cm^2*20cm
2*10^10cm^3
%
23%=x/(x+2*10^10)*100%
x=5.974*10^9cm^3