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4 years ago

Simplify the expression if possible by combining like terms 9(X+5)+7(X-3)

1 answer:

7 0

So you do
distribute
a(b+c)=ab+ac
9(x+5)=9x+9 times 5=9x+45

7(x-3)=7x+7 times -3=7x-21

so now we have
9x+45+7x-21
group like terms
9x+7x+45-21
add
16x+24

simplified is 16x+24

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Solve: 12^x2+5x-4 =12^2x+6

lyudmila [28]

Answer:

x=2, x=-5

Step-by-step explanation:

to work more comfortably, the first thing we need to do is work the equation linearly, for that we take advantage of the property of logarithms that tells me that $log(a^{b})=b*log(a)$

in this way, the equation remains as:

$log(12^{x^{2} +5x-4 } )=log(12^{5x+6} ) \\ (x^{2} +5x-4 )*log(12)=(5x+6) *log(12)\\x^{2} +5x-4 = 5x+6$

Now we clear the equation so that it is of the form $ax^{2} +bx+c=0$

$x^{2} +5x-2x=6+4\\ x^{2} +3x-10=0$

finally, we apply the equation to solve second degree equations

$x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$

$x = \frac{-3 \pm \sqrt {3^2-4*1*(-10)}}{2*1}\\ x = \frac{-3 \pm \sqrt {9+40}}{2}\\ x = \frac{-3 \pm 7}{2}$

x=2 and x=-5

Done

5 0

4 years ago

Mrs. Smith went to the grocery store and bought the fruit below.

lukranit [14]

The answer is 12.69, you just need to put all the groceries together!!

7 0

3 years ago

SOCCER PRACTICE BEGAN AT 2:30 P.M 3:30 P.M THROUGH WHAT FRACTION OF A CIRCLE DID THE MINUTE HAND TURN HOW MANY DEGREES DID THE M

MrMuchimi

Answer:

1 /1 ; 360°

Step-by-step explanation:

Start time = 2:30 pm

Stop time = 3:30 pm

Minute hand makes a complete revolution per hour ;

This means that the minutes hand revolves round the whole circle in one hour, hence fraction of the circle covered by the minute hand between 2:30 pm - 3:30 pm is 1/1 = 1

The angle turned by the minutes hand :

1 complete revolution = 360°

A circle covers 360°

1 /1 fraction of a circle = 1/1 * 360° = 360°

Hence, angle turned by the minute hand = 360°

5 0

3 years ago

(iii) (3x + 4)(3x - 5)

kiruha [24]

Answer:

$x_{1}=-\frac{4}{3}\\x_{2}=\frac{5}{3}\\$

Step-by-step explanation:

$(3x+4)(3x-5)=9x^{2} -15x+12x-20=9x^{2} -3x-20\\\\9x^{2} -3x-20=0\\\\D=b^{2} -4ac=(-3)^{2}-4*9*(-20)=9+720=27^{2} \\\\x_1_,_2=\frac{-b +_- \sqrt{D} }{2a}\\\\x_1=\frac{3-27}{18}=\frac{-24}{18} =-\frac{4}{3}\\\\x_2=\frac{3+27}{18}=\frac{30}{18} =\frac{5}{3} \\\\$

6 0

3 years ago

Which of the following shows the equation solved for y?<br> 2x + 6y = -12

oksano4ka [1.4K]

Answer:

Here it goes -0.333

6 0

4 years ago