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3 years ago

Tell me a joke, who ever's joke I like better will get a Brainlist

Mathematics

2 answers:

morpeh [17]3 years ago

7 0

Here’s a joke

What did the baby mushroom say to the mom mushroom?

I don’t have mush-room
(much room)

Me:

FromTheMoon [43]3 years ago

6 0

I wanted to be king because I saw dream of king

one day when I visit to dentist

Dentist: "You need a crown." -

Patient: "Finally someone who understands me"

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HELP PLS<br> Solve for x<br> x=[?]<br> 3x + 2 6x - 20

Sloan [31]

Step-by-step explanation:

Remember that the sum of angles on a straight line are supplementary. (180°)

Therefore 3x + 2 + 6x - 20 = 180.

=> 9x - 18 = 180

=> 9x = 198

=> x = 22.

3 0

3 years ago

Name the values of the 5s in 5,500

Mademuasel [1]

Answer:

5 thousand and 5 hundred.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A gardener measured the heights of two plants at the end of every week. The function y=3x+8.5 gives the hight of plant a in cent

MAVERICK [17]

Answer:

12 weeks

Step-by-step explanation:

Step one:

given data

let the heights of the plants be y

and the number of weeks be x

Plant A

y=3x+8.5--------------1

Plant B

y=2.5x+14.5----------2

Required

The number of weeks taken for both plants to have the same height

,equate the two expressions above

3x+8.5=2.5x+14.5

3x-2.5x=14.5-8.5

0.5x= 6

divide both sides by 0.5

x= 6/0.5

x= 12 weeks

6 0

3 years ago

A dodecahedron is a Platonic solid with a surface that consists of 12 pentagons, each of equal area. By how much does the surfac

Nastasia [14]

Answer:

12 times 2 since it doubles every time I'm not that sure so if I am not correct my bads

4 0

2 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago