Let, Your Integers = x, x+2, x+4
Now, x + x+2 + x+4 = 93
3x + 6 = 93
3x = 93 - 6
x = 87/3
x = 29
Then, x+2 = 31, & x+4 = 33
In short, Your Integers would be 29, 31, 33
Hope this helps!
Answer:
is 0.75d becase the missing numbers should be the same number
From the solution of the expression, it can be seen that s = 6 when t = 3 while t = 1 when s = 2.
<h3>How do we solve a mathematical expression?</h3>
Given:
(12t) = (6s) ........................ (1)
When t = 3, we can solve for s from the expression in equation (1) by substituting t = 3 into the equation as follows:
12 * 3 = 6s
36 = 6s
s = 36 / 6
s = 6
When s = 2, we can solve for t from the expression in equation (1) by substituting s = 2 into the equation as follows:
12t = 6 * 2
12t = 12
t = 12 / 12
t = 1
Learn more about mathematical expression here: brainly.com/question/12401681.
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The answer is C.
SA = bh + (s1 + s2 + s3)H
SA = (6.8)(5.1) + (6.8 + 5.1 + 8.5)(2.5) = 85.68
Okay so like, all you've gotta do is multiply 567 by 48 & add 1250. Leaving you with the answer of 28,466