Base=x+7 Height=x Area=60. 60=((x+7)(x))/2----->60=(x^2+7x)/2
120=x^2+7x X^2+7X-120=0. QUDRATIC FORMULA: -7+/- SQRT(49+480)/2
(-7+/-23)/2... 8 and -15. -15 ISNT the answer because you cant have a negative length. X=8 Base=8+7---->15 Height=8
Well it is true if the problem is the right with the right answer. If not you have a false eqaution.
When you don't use or write the percent right.<span />
SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm