To find the next term in an arithmetic sequence, your best bet would be to use the formula N(x)= N(1) + (x-1)*d, where x stands for the term you want to find, N(1) stands for the first number in the sequence, and d stands for the common difference between the numbers.
First, lets see what we can plug in. We know the first term in the sequence (N(1)) is 11, we know that we want to find the 23rd number in the sequence (x), and by subtracting the 2nd term by the 1st term (14-11), the common difference (d) is 3. When we plug that all into our equation, it should end up looking something like this: N(23)= 11 + (23-1)*3.
Next, we can break down the equation to solve it step by step using PEMDAS. Parenthesis go first, so N(23)= 11 + (23-1)*3 becomes N(23)= 11 + (22)*3. We don't have any exponents, so we can skip the E. Next, we do multiplication and division from left to right, so N(23)= 11 + (22)*3 becomes N(23)= 11 + 66. Finally, we do addition and subtraction from left to right, getting us from N(23)= 11 + 66 to N(23)= 77, which means that the 23rd number in the sequence is 77!
Answer:
Vertical compression: the squeezing of the graph toward the x-axis
Horizontal stretch: the squeezing of the graph toward the y-axis
p(-5, 2)
the rule is x + 3, so add -5 + 3 = -2
the x coordinate of P' is -2
2(7/2)^x = 49/2
Divide both sides by 2:
(7/2)^x = 49/4
I notice that 49/4 can be rewritten as (7/2)^2, so we now have:
(7/2)^x = (7/2)^2
The only way for this to be true is if x = 2. Thus, we are done.
Answer:
f (x) = -2 (x + 6)^2 + 2
Step-by-step explanation:
f (x) = -2x^2 - 24x - 70 <--- divide out -2 out of the first two terms...
f (x) = -2 (x^2 + 12x) - 70 <-- divide the x coefficient by 2 and then square it, then add AND subtract it)
f (x) = -2 (x^2 + 12x + (12/2)^2 - (12/2)^2) - 70
f (x) = -2 (x^2 + 12x + 36 - 36) - 70 <--- distribute the -2 onto -36 to get it out of the brackets..
f (x) = -2 (x^2 + 12x + 36) + 72 - 70 <-- combine constants and factor perfect square trinomial...
f (x) = -2 (x + 6)^2 + 2 <-- standard form...
