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Sedbober [7]
3 years ago
14

What is the equation in point-slope form of the line passing through (1, 9) and (−1, 11)?

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0
Point slope form: 
y-y_1=m(x-x_1)

m=slope 
(x1,y1) 

First we need to find the slope using the slope formula:
\frac{y_2-y_1}{x_2-x_1} =slope

Given the two coordinates: 
<span>(1, 9) and (−1, 11)

Plug them into the slope formula: 
</span>\frac{11-9=2}{-1-1=-2} =slope
Simplify: 
\frac{2}{-2} =-1
<span>
Now we know that: 
m=-1  and the (x1,y1) would be </span><span>(1, 9)
</span>
Now we simply plug in the info: 
y-9=-(x-1)

Final answer: y − 9 = −(x − 1)
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If Alex and Mpho have to share R20 in the ratio 2:3,how much will Mpho get?
CaHeK987 [17]

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D

Step-by-step explanation:

sum of ratio=2+3=5

Mpho gets=3/5×20=12

4 0
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“the product of 6 and<br> 9 decreased by 8"
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Answer:

46

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“the product of 6 and 9 decreased by 8"

“the product of 6 and 9" = 6 * 9

"decreased by 8" = - 8 (subtract 8 from whatever, in this case 6 * 9)

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5 0
2 years ago
Analyze the diagram below and complete the instructions that follow.
lora16 [44]

Answer:

\displaystyle y=2\sqrt{6}

\displaystyle x=2\sqrt{2}

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.

Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:

\displaystyle \cos 30^\circ=\frac{\text{adjacent leg}}{\text{hypotenuse}}

\displaystyle \cos 30^\circ=\frac{y}{4\sqrt{2}}

Solving for y:

y=4\sqrt{2}\cos 30^\circ

Since:

\cos 30^\circ=\frac{\sqrt{3}}{2}

\displaystyle y=4\sqrt{2}\frac{\sqrt{3}}{2}

Simplifying:

\displaystyle y=2\sqrt{6}

Now we use the sine ratio:

\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}

\displaystyle \sin 30^\circ=\frac{x}{4\sqrt{2}}

Solving for x:

x=4\sqrt{2}\sin 30^\circ

Since:

\sin 30^\circ=\frac{1}{2}:

\displaystyle x=4\sqrt{2}\frac{1}{2}

Simplifying:

\displaystyle x=2\sqrt{2}

The choices are not clear, but it seems like the correct answer is C.

\boxed{\displaystyle y=2\sqrt{6}}

\boxed{\displaystyle x=2\sqrt{2}}

6 0
3 years ago
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