The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground?
Answer: In order to find the stone’s velocity just before it strikes the ground we will use one of the free fall equations. V = √(2gh). We already have the values needed which are the gravity (9.8 m/s2) and our total height (318 meters). All you have to do is solve for V. You should get 78.95 m/s.
Answer:
(4,2)
Step-by-step explanation:
Solving the system of equations means to find the dot where both the lines intersect. We know by the graph that the point where the both intersect is (4,2).
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Answer:
C
Step-by-step explanation:
the sum of complementary angles = 90°, hence
x + 5 + x - 9 = 90
2x - 4 = 90 ( add 4 to both sides )
2x = 94 ( divide both sides by 2 )
x = 47
Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°
Answer:
−7b−9k+6
Step-by-step explanation:
−4b+(−3b)=−7b
+(−9k)=−9k
12−6=6
Answer:
I think the answer is 1/42