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san4es73 [151]
3 years ago
12

At the end of 8 years, Anna paid $400 interest for a loan. If the simple annual interest rate was 4%, how much did Anna borrow?

A. $1250 B. $1080 C. $864 D. $432
Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

A.)$1250

Step-by-step explanation:

Have a nice day

TiliK225 [7]3 years ago
4 0

Answer:

<h2>$1250</h2>

Step-by-step explanation:

Use the formula i = prt

First, converting R percent to r a decimal

r = R/100 = 4%/100 = 0.04 per year,

then, solving our equation

P = 400 / ( 0.04 × 8 ) = 1250

P = $ 1,250.00

The principal required to

accumulate interest of $ 400.00

on a rate of 4% per year for 8 years is $ 1,250.00.

<h3><u>Brainliest Please!</u></h3>
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lesya [120]

Answer:

C

Step-by-step explanation:

(x, y) -> (1/2x, 1/2y)

When you dilate a side, point, etc, you are multiplying the original dimension by the scale factor. That is represented in option C: the original x and y are multiplied by the scale factor, 1/2! Hope that helps! :)

6 0
4 years ago
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a bag contains colored gumdrops 5 are cherry 3 are strawberry 2 are grape. a gumdrop will be randomly selected from the bag what
weqwewe [10]

Answer:

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Step-by-step explanation:

here's the solution : -

probablity of grapes =

\frac{number \: of \: grapes}{total \: fruits}

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6 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.
WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = \frac{1}{tanx}

csc² x = 1 + cot² x

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tanθ = \sqrt{3} , then cotθ = \frac{1}{\sqrt{3} }

csc²θ = 1 + (\frac{1}{\sqrt{3} } )² = 1 + \frac{1}{3} = \frac{4}{3}

cscθ = ± \sqrt{\frac{4}{3} } = ± \frac{2}{\sqrt{3} }

Since θ is in 3rd quadrant, then cscθ < 0

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8 0
3 years ago
An amusement park ride has cars that move around a circular track at the rate of 16 revolutions in 20 seconds. To the nearest hu
astraxan [27]

Answer:

5.03\frac{rad}{sec}

Step-by-step explanation:

To find the angular velocity divide the revolutions by the time

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Remember that

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Convert rev/sec to rad/sec

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assume \pi=3.1416

1.6(3.1416)=5.03\frac{rad}{sec}

6 0
4 years ago
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