Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
-4+5n=18+3n=? so n=18+3n group like terms which would be
18+4n my beautiful queen
hope this helps
A dozen is 12 and since 4 is a multiple of 12, I did 12 divided by 4 which is three. So i did 3.50 multiplied by 3 and the answer is 10.50
Answer:
8v^2+24-48x^3
Distribute the -8 to each term to get your answer.
Hope I helped!
19.30 - ( p / 100 )*19.32 = 14.01 ;
19.30( 1 - p/100 ) = 14.01 ;
1 - p/100 = 14.01 / 19.30
1 - p / 100 = 0.72 ;
p/100 = 1 - 72 / 100 ;
p/100 = 28 / 100 ;
p = 28 ;
The percent discount is 28% ;
