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DIA [1.3K]
3 years ago
8

How do you write 5x - 4y = 1 in slope intercept form

Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0

First move the 4y to the right and the 1 to the left:

4y=5x-1

Then divide everything by 4:

y=5/4 x - 1/4

Helga [31]3 years ago
6 0

that how you write it in slope intercept form

m=-5/4

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I’m having trouble understanding how to solve this someone please help ASAP thank you!
vladimir2022 [97]

Answer:

Answer is 71.95°

Step-by-step explanation:

Cosine formula is

a^2=b^2+c^2-2bc(cosA)

cos A =b^2+c^2-a^2/2bc

if a= 119,b=94,c=173

cos A=94^2+173^2-119^2/2(94*173)

=8836+29,929-14,161/2(16,262)

=38765-14,161/32,524

=24604/32,524

=0.7564

cos A=0.7564

cos^-1=40.85°.that's for angle A.

Using the same formula

B=31.1°

C=180-(40.85+31.1)

C=180-71.95

C=108.05

Since angle on a straight line is 180

therefore x is 71.95

Also the sum of angles A and B

3 0
1 year ago
(linear functions) PLEASE HELP!!! WILL GIVE BRAINLIEST
fredd [130]
There are 3 units between y int. One is at y=0 and the other is y=-3
5 0
2 years ago
Read 2 more answers
Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba
nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

n = 12, p = 0.5

(a) 2 or 5 children

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208

P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537

P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161

P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029

P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0
3 years ago
Somebody please help ASAP!!!
Butoxors [25]
The answer is -6x+85

7 0
3 years ago
If car #1 gets 43.2 miles per gallon and car #2 gets 35.9 miles per gallon. Calculate the difference in costs if you drive a dis
Tanzania [10]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~

Car #1: 300/43.2 = 6.9444 gallons

(Rounded) Car #2: 300/35.9 = 8.3565 gallons

~~~~~~~~~~~~~~~~~~~~~~~~~

(Rounded) Car #1: 6.9444*3.19 = $22.16 to re-fill their tank

(Rounded) Car #2: 8.3565*3.19 = $26.66 to re-fill their tank

~~~~~~~~~~~~~~~~~~~~~~~~~

(Rounded) Difference: $26.66 - 22.15 = $4.50

To re-fill Car 2's tank is approximately $4.50 more to re-fill Car 1's tank...

8 0
3 years ago
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