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pav-90 [236]
3 years ago
5

Penny needs 30 cubic ft of sand to fill a sandbox. She plans to buy 10 bags of sand for her sandbox. Each bag contains 2.9 cubic

feet of sand. Is this a reasonable plan? A. Yes, it is reasonable because each bag covers around 3 cubic feet. So in order to cover 30 cubic feet she would need 10 bags to be sure she has enough and end up with a little extra. B. No, it is not reasonable because each bag covers around 3 cubic feet. So in order to cover 30 cubic feet, she would need at least 30 bags to be sure she has enough sand. C. No, it is not reasonable because each bag covers a bit less than 3 cubic feet. So in order to cover 30 cubic feet, she would need to buy 11 bags to be sure she has enough sand
Mathematics
1 answer:
Romashka [77]3 years ago
4 0
The correct answer is C.

Because: 2.9 multiplied by 10 bags equals 29cubic ft and she needs 30 cubic ft. So she would need to buy 11 bags to make sure she has enough sand for the whole thing. 11 x 2.9 = 31.9 which ensures she has enough for the whole thing including extra in case. So you answer would be Answer C.
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It takes 8 workers 5 hours to build 2 cars. Assuming they work at the same speed , how long does it take 2 workers to build 8 ca
vodomira [7]

Answer:

80 hours   for 2 workers  to build 8 cars

Step-by-step explanation:

2 cars / 8w *5 hr  =   2 cars / 40 hrs    1 car takes 20 hrs

8 cars * 20 hours = 160 hours required

 two workers split this time    160/2  = 80 hours

8 0
2 years ago
Isaac and Albert spot a hot air balloon flying at a low altitude. They decide to calculate its height by standing 400 feet apart
yarga [219]

Answer:

144 feet to nearest foot.

Step-by-step explanation:

Let the distance between Albert and the point on the ground that the balloon is directly above be x feet Then for Isaac the distance is 400 - x feet

So we have 2 right angled triangles and:

tan 62 = h/x

tan 48 = h / (400- x)         where h is the height of the balloon.

From the first equation x = h / tan 62 so plugging this into the second one:

tan 48 =  h /  ( 400 - h/tan 62)

h = 400 tan 48 - h tan 48 tan 62

h + h tan 48 tan 62 = 400 tan 48

h ( 1 + tan48 tan62) = 400 tan48

h = 400 tan 48 / (1 +  tan 48 tan 62)

= 143.8 feet.

4 0
3 years ago
Can the distributive property be used to rewrite 6*(8-5)? Yes or no?
UkoKoshka [18]
Yes you can distribute.
6(8-5)
(6*8) - (6*5)
3 0
3 years ago
Help help help timed exam please
LUCKY_DIMON [66]

Answer:

The correct option is the second option;

a. Division property of equality

b. Symmetric property of congruency

c. Multiplication property of equality

Step-by-step explanation:

a. For the equation in part a., we have;

6·a = 30

Therefore;

6·a/6 = 30/6

a = 5

Which is of the form, if a = b then a ÷ c = b ÷ c, which is the division property of equality

b. For the relationship in part b., we have;

∠ABC ≅ ∠LMN

∠LMN ≅ ∠ABC

The above relationship is of the form, if a ≅ b then b ≅ a, which is the symmetric property of congruency

c. For the equation in part c., we have;

\dfrac{2}{3} \cdot \left (x - 6\right ) = 8

Multiply both sides by 3, to get;

3 \times \dfrac{2}{3} \cdot \left (x - 6\right ) = 3 \times 8 = 24

Cancel like terms on the left hand side of the equation, to get;

2·(x - 6) = 24

Which is of the form, if a = c, then a × c = b × c which is the multiplication property of equality

5 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. It forms a pile in the shape of a right circu
Sunny_sXe [5.5K]

Answer:

0.0221 feet per minute.

Step-by-step explanation:

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

Rate of Change of the Volume, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Since gravel is being dumped from a conveyor belt at a rate of 10 cubic feet per minute. Therefore, the Volume of the cone is increasing at a rate of 10 cubic feet per minute.

\dfrac{dV}{dt}=10$ ft^3/min

We want to determine how fast is the height of the pile is increasing when the pile is 24 feet high.

We have:

\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10\\\\$When h=24$ feet$\\\dfrac{3\pi *24^2}{12}\dfrac{dh}{dt}=10\\144\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{144\pi}\\ \dfrac{dh}{dt}=0.0221$ feet per minute

When the pile is 24 feet high, the height of the pile is increasing at a rate of 0.0221 feet per minute.

4 0
3 years ago
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