Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflec
tion of the parent function over the x-axis.
Use the sine tool to graph the function.
The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
Use the sine tool to graph the function.
The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
1 answer:
Answer:
y=4sin(2x) - 3
Step-by-step explanation:
Recall the form of a sinusoidal function is Asin(Bx + C) + D, where A is the amplitude, B is the frequency (could also be viewed as the period), C is the horizontal (phase) shift, and D is the vertical shift. Also, recall sin(x) has a period of 2π.
You start with the parent function (sin(x)).
Then, knowing the amplitude is 4: 4sin(Bx + C) + D
Then, knowing the period of the regular sine function is 2π, to get to a period of π, divide by 2 (the period of the curve changes by a factor of 1/2), so your B coefficient is 2: 4sin(2x + C) + D
There is no phase shift, so omit C: 4sin(2x) + D
Since the midline is y = -3, that is your vertical shift (D): 4sin(2x) - 3
Graph of y = 4sin(2x) - 3 is below:
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Answer:
The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.
The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.
A random sample of <em>n</em> = 111 keypads is analyzed.
Then the sampling distribution of is:
Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:
Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.