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aalyn [17]
3 years ago
5

Imagine looking through a microscope at a squashed onion root tip. The chromosomes of many of the cells are plainly visible. In

some cells, replicated chromosomes are aligned along the center (equator) of the cell.
These particular cells are in which stage of mitosis?

A) telophase
B) prophase
C) anaphase
D) metaphase
E) prometaphase
Biology
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

D) metaphase

Explanation:

Mitosis is a type of cell division in which the cell divides its replicated chromosome in equal amount in two daughter cells. Mitosis takes place in four phases: Prophase, Metaphase, Anaphase and Telophase.

Metaphase is the stage of the cell division during which the chromosome is present in the highly condensed form present in the centre of the cell. The chromosomes are aligned at the equator of the cell.

Thus, metaphase is the correct answer.

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Identification of key microRNAs and the underlying molecular mechanism in spinal cord ischemia-reperfusion injury in rats
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The underlying molecular processes for 19 important DE miRNAs in the etiology of SCII were confirmed. The DE miRNAs could serve as potential intervention targets for SCII. Additionally, blocking microRNAs-3568 reduced apoptosis and preserved hind limb function after SCII, possibly via modulating GATA6, GATA4, and RBPJ in SCII.

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  • SCII (spinal cord ischemia-reperfusion damage) is a medical condition that can lead to paralysis and paraplegia, among other serious effects. The development of SCII is influenced by aberrant microRNAs expression. Different microRNAs expression results could be caused by variations in the experimenters, filtering circumstances, control choice, and sequencing platform.
  • The purpose of this study is to investigate the important differently expressed microRNAs (DE miRNAs) and the underlying molecular mechanism in SCII by methodically analyzing the available SCII microRNAs expression data. A thorough bioinformatics study of 23 representative rat SCII miRNA datasets from PubMed was carried out. On mi RDB, the target genes of important DE miRNAs were predicted.
  • Functional enrichment and transcription factor binding analyses using the DAVID and T Fact S databases. Nine were increased (miR-144-3p, miR-3568, miR-204, miR-30c, miR-34c-3p, miR-155-3p, miR-200b, miR-463, and miR-760-5p) and ten were downregulated (this study found 19 important DE miRNAs involved in SCII) (miR-28-5p, miR-21-5p, miR-702-3p, miR-291a-3p, miR-199a-3p, miR-352, miR-743b-3p, miR-125b-2-3p, miR-129-1-3p, and miR-136).Target genes of the increased DE miRNAs underwent KEGG enrichment analysis, which identified the pathways primarily involved as being the cGMP-PKG and cAMP signaling pathways. According to KEGG enrichment analysis of the downregulated DE miRNAs' target genes, the main signaling pathways involved were the Chemokine and MAPK signaling pathways. The target genes of the increased DE miRNAs were clearly enriched in biological processes such brain development and the positive control of transcription from RNA polymerase II promoter, according to GO enrichment analysis.
  • The majority of the target genes of the downregulated DE miRNAs were enriched in biological processes such intracellular signal transmission and the inhibition of cell growth. The transcription factor study revealed that the four transcription factors, SP1, GLI1, GLI2, and FOXO3, had significant regulatory effects on the main DE miRNAs' target genes. MiR-3568 stood out among the elevated DE miRNAs as being particularly intriguing. SCII results in significant neurological deficiencies in the lower extremities, but miR-3568 anti-miRNA oligonucleotides (AMOs) enhance neurological performance. When compared to the sham group, cleaved caspase-3 and Bax were significantly elevated in SCII, however the overexpression was inhibited by miR-3568 AMO. In contrast to cleaved caspase-3, Bcl-2 expression levels exhibited a pattern. Following the attenuation of this increase by SCII and microRNAs-3568 AMO, the expression of GATA6, GATA4, and RBPJ reduced.

Learn more about microRNAs here brainly.com/question/14979443

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The correct answer is:  5) NER recognizes helix distortions, while BER recognizes specific base damage.

DNA damage that occurs as a result of radiation, oxidizing reagents, chemicals and other mutagens can be repaired. Excision repair repairs single strand DNA damage and it includes:

• Nucleotide excision repair (NER)-it detects and repairs types of damage that distort the DNA double helix such as those of UV radiation (thymine dimers); not only the damaged nucleotide(s) are removed but also a surrounding patch of DNA

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10.1 Limits To Cell Growth
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Answer:

Cell size is determined by joint regulation of cell size and cell cycle duration.

Size dependent modulation of growth rate allows maintenance of cell size homeostasis.

Central carbon metabolism is key regulator of both cell size and cell cycle.

Size dependent regulation of metabolism and growth rate implies cell size sensing. As the cell increases in size the volume of the cell increases more rapidly than the surface area which causes a decrease in the cell's ratio of surface area to volume and makes it more difficult for the cell to move needed materials in and waste products out.

DNA- variety of genes are involved in the control of cell growth and division. The cell cycle is the cell’s way of replicating itself in an organized, step-by-step fashion. Tight regulation of this process ensures that a dividing cell’s DNA is copied properly, any errors in the DNA are repaired, and each daughter cell receives a full set of chromosomes. The cycle has checkpoints (also called restriction points), which allow certain genes to check for problems and halt the cycle for repairs if something goes wrong. If a cell has an error in its DNA that cannot be repaired, it may undergo programmed cell death (apoptosis). Apoptosis is a common process throughout life that helps the body get rid of cells it doesn’t need. Cells that undergo apoptosis break apart and are recycled by a type of white blood cell called a macrophage. Apoptosis protects the body by removing genetically damaged cells that could lead to cancer, and it plays an important role in the development of the embryo and the maintenance of adult tissues. Cancer results from a disruption of the normal regulation of the cell cycle. When the cycle proceeds without control, cells can divide without order and accumulate genetic defects that can lead to a cancerous tumor.

Nutrients and waste- The larger a cell becomes, the more demands the cell places on its DNA. In addition, the cell has more trouble moving enough nutrients and wastes across the cell membrane. The resulting decrease in the cell's ratio surface area to volume makes it more difficult for the cell to move needed materials in and waste products out.

Surface area of the cell- The amount of surface area available to each unit of the cell depends on the size of the cell. As a cell grows, it's surface area/volume ration decreases. At some point of the cells growth, the surface area/volume ratio becomes so small that the surface area is too small to supply raw materials to its volume. materials cannot enter the cell if the surface is too large. ... the cell may become too large to take in enough food and to remove enough wastes. waste products cannot leave the cell if the cell is too small.

Cell volume-

Explanation:

Hope this is helpful?

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