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3 years ago

Please help, totally confused :(((

Biology

1 answer:

sertanlavr [38]3 years ago

4 0

The median for group 2 is almost double the median for group 1. Group 2's median would be 80, and 1's would be a little over 40, which is about half. The median is the middle line of the box on the graph.

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Explain how chromosome behavior during meiosis ensures transfer of parental traits to offspring

gizmo_the_mogwai [7]

Explanation:

During meiosis, sister chromosomes of a homologous pair separate into different cells during gamete formation . This mainly occurs in Metaphase I of meiosis where the homologous chromosomes line up the metaphase plate in their sets. Each chromosomes of a pair are then pulled to different poles of the cells separating them. Each of these chromosomes carries a set of alleles of a gene. Each cell/gamete, therefore, carried half the set of alleles of all genes compared to autosomal cells. There many combinations of these sets that can occur depending on the number of chromosomes the organism has.

These cells when combined with that of another parent during fertilization, form a zygote that grows and develops into a mature organism. The offspring will bear the characteristics of both parents because it inherits half a set of chromosomes from both parents.

Learn More:

For more on meiosis check out;

brainly.com/question/11701550

brainly.com/question/1271878

#LearnWithBrainly

6 0

3 years ago

Read 2 more answers

HELP QUICK-Which of the following is true regarding the atoms involved in a chemical reaction?

NeTakaya

Answer:

The same number of each type of atom will always be present before and after a chemical reaction takes place.

Explanation:

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3 years ago

Bearing fruit benefits plants because

Pavlova-9 [17]

Answer:

There are many benefits of bearing fruits. Please read the explanation section.

Explanation:

A fruit is the part of flowering plants. Fruit contains the seeds of the plant. These seeds help the plants to reproduce its next generation. Some fruits are fleshy like berries; some are hard like nuts. The fruit helps to protect the seeds.

Along with this, the fruit helps the seeds to be spread out. Many fruits are attractive because of their color and aroma. They attract small animals like birds, squirrels. They eat those fruits. After eating, the animals move from one place to another. With them, the seeds move too. When those animals poop, the seeds are coming out with their poop. Then the seed can grow at that place.

4 0

3 years ago

Which characteristic of a protein may change during a DNA mutation?

patriot [66]

Answer:

Sequence of amino acids by the ribosome are the characteristic of a protein may change during a DNA mutation. Explanation: Point mutations can cause significant changes to an organism if they alter the way a protein functions. A mutation in DNA changes the mRNA, which in turn will change the amino acid chain.......

Explanation:

3 0

2 years ago

Read 2 more answers

The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago