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Vera_Pavlovna [14]
4 years ago
5

V

Mathematics
1 answer:
iris [78.8K]4 years ago
5 0

Answer:

Step-by-step explanation:

1294000

I think.

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y=x

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19−4c=17 Solve the equation
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19-4c=17

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A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the
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Answer:

a) 15.4% probability that a randomly selected person in this country is 65 or older

b) 0.023 = 2.3% probability that the person is 65 or older

Step-by-step explanation:

To solve b), i will use the Bayes Theorem.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.7% of people in the county are under age 18

61.9% are ages 18–64

p% are 65 or older.

The sum of those is 100%. So

22.7 + 61.9 + p = 100

p = 100 - (22.7+61.9)

p = 15.4

15.4% probability that a randomly selected person in this country is 65 or older.

(b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

Event A: Uninsured

Event B: 65 or older.

15.4% probability that a randomly selected person in this country is 65 or older.

This means that P(B) = 0.154

1.4% of those 65 and older do not have health insurance.

This means that P(A|B) = 0.014

Probability of not having insurance.

22.7% are under 18. Of those, 5.4% do not have insurance.

61.9% are aged 18-64. Of those, 12.8% do not have insurance.

15.4% are 65 or over. Of those, 1.4% do not have health insurance. So

P(A) = 0.227*0.054 + 0.619*0.128 + 0.154*0.014 = 0.093646

Then

P(B|A) = \frac{0.154*0.014}{0.093646} = 0.023

0.023 = 2.3% probability that the person is 65 or older

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