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Snowcat [4.5K]
3 years ago
8

The total amounts of rainfall at various points in time during a thunderstorm are shown in the table. Rainfall During a Thunders

torm Time (hours) 0.4 1.1 2.9 3.2 3.7 4.4 Rainfall (cm) 0.3 0.6 1.8 2.0 2.2 2.6 According to a regression calculator, what is the equation of the line of best fit for the data? A calculator screen. A 2-column table with 6 rows titled Data. Column 1 is labeled x with entries 0.4, 1.1, 2.9, 3.2, 3.7, 4.4. Column 2 is labeled y with entries 0.3, 0.6, 1.8, 2, 2.2, 2.6. The linear regression equation is y almost-equals 0.594 x + 0.029; r almost-equals 0.998. y almost-equals 0.06 x + 0.03 y almost-equals 0.06 x + 0.29 y almost-equals 0.59 x + 0.03 y almost-equals 0.59 x + 0.29
Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

y approximately is equal to 0.59x + 0.03, the third option.

Step-by-step explanation:

Took the test,

beks73 [17]3 years ago
5 0

Answer:

C. y almost-equals 0.59 x + 0.03

Step-by-step explanation:

The linear regression equation is y ≈ 0.594 x + 0.029; r ≈ 0.998.

0.594 must be rounded down to 0.59 (digits finished in 1, 2, 3 and 4 are rounded down)

0.029 must be rounded up to 0.03 (digits finished in 5, 6, 7, 8 and 9 are rounded up)

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Mel used partial quotients to find the quotient of 378 divided by 3.What could be the partial quotient that Mel found?
Genrish500 [490]

Answer:

The partial quotients are 100, 20 and 6. The quotient is 126.

Step-by-step explanation:

The dividend is 378 and the divisor is 3.

First find the factors of 3, near to 300.

3\times 1=3

3\times 10=30

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The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.

Now the remaining divide is 78.

First find the factors of 3, near to 78.

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3\times 30=90

Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.

Now the remaining divide is 18.

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The number 6 is a partial quotient.

Therefore  partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.

100+20+6=126

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Solve for substitution 8x+2y=13 and 4x+y=11
damaskus [11]
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The answer is x=6. I double checked the work and am 100% sure thats the answer

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