What the heck do i do with this

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

There are 1420 students enrolled at Senn. If 60% of these students walk to school, how many students are walking to school?

pychu [463]

Answer:

852 students walking to school

Step-by-step explanation:

Lets start with a simple example so you can get it

if 60% of 100 students walk to school that means

60 students walk to school... right??

so lets simplify it more that means you have multiplied 100 (students) by 60%

or $\frac{60}{100}$ (note: you can say that 60% is equal to $\frac{60}{100}$ )

so the problem told 60% of 1420 students walk to school that means we should

do this: $1420*\frac{60}{100} = 852$

3 0

3 years ago

Read 2 more answers

Write an equation that represents the line. Use exact numbers

aev [14]

Answer:

y= 2/3x + 1.25

Step-by-step explanation:

I can't see the exact number but it's probably 1.25. Sorry if it's wrong :)

5 0

3 years ago

Catherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tub

erastova [34]

She can buy 3 tubes be cause 8.50 time 2 is less then 20$ but 8.50 times three is more than 20$ its 25.5

3 0

3 years ago

Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla

hram777 [196]

Answer:

Hello! I think the answer is D: $2.25. Please correct me if i'm wrong.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers