The measures of central tendency, fancy words for the middle, are
C. Mode
D. Mean
E. Median
Simplify
= 6/(gf^4)
hope that helps
<h2>
Explanation:</h2>
In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.
So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.
So let's name the vertices as:

First pair of opposite sides:
<u>Slope:</u>

Second pair of opposite sides:
<u>Slope:</u>

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

So the diagonals measure the same, therefore this is a rectangle.
Never. If they are not on the same plane, then they cannot intersect because 2 lines and 1 point are always on a plane, in this case the original line, then a point in the middle to the point that creates the other line would be included, hence if they are non-coplaner then they cannot intersect.
<span>cross is my best answer</span>