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olga55 [171]
3 years ago
15

The area formed by a plane cutting through a solid perpendicular to its axis is a

Mathematics
2 answers:
kvasek [131]3 years ago
8 0
<span>cross is my best answer</span>
blsea [12.9K]3 years ago
6 0

Answer:

cross section

Step-by-step explanation:

The area formed by a plane cutting through a solid perpendicular to its axis is a cross section.

A cross section area is the area obtained from a three dimensional object like sphere when it is sliced at any axis perpendicular at a point. For example cross section of a cylinder sliced parallel to its base is circle.

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What is the absolute value of the square root of 5 minus 5?
OLEGan [10]

-2.7639320225 is the exact when estimated -3 hope this helped if can pls mark as brainliest have a great day!

6 0
3 years ago
Find a formula for the inverse of the function. f(x) = e^6x − 9
STatiana [176]

Answer:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

Step-by-step explanation:

So we have the function:

f(x)=e^{6x}-9

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

x=e^{6f^{-1}(x)}-9

Add 9 to both sides:

x+9=e^{6f^{-1}(x)}

Take the natural log of both sides:

\ln(x+9)=\ln(e^{6f^{-1}(x)})

The right side cancels:

\ln(x+9)=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

And we're done!

7 0
3 years ago
An element with mass 730 grams decays by 27.6% per minute. How much of the element is remaining after 12 minutes, to the nearest
Korolek [52]
\bf \qquad \textit{Amount for Exponential Decay}\\\\&#10;A=I(1 - r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &730\\&#10;r=rate\to 27.6\%\to \frac{27.6}{100}\to &0.276\\&#10;t=\textit{elapsed time}\to &12\\&#10;\end{cases}&#10;\\\\\\&#10;A=730(1-0.276)^{12}\implies A=730(0.724)^{12}
8 0
3 years ago
Read 2 more answers
HI CAN SOMEONE PLZ HELP ME I HAVE NO CLUE HOW TO DO THIS SOS. THANKS SM!!!❤️❤️❤️
Kitty [74]

Problem 1)

This question is incomplete. It asks us to find something, but doesn't say what to find. It's literally blank after the word "find" which suggests your teacher made a typo. Please get back to me on this. Thanks.

===================================

Problem 2)

Angles GAR and GAT are supplementary because they are a linear pair. They form a straight angle. So we add up the expressions of x for each of these angles, solve for x, and use this to find angle GAR.

(angle GAR) + (angle GAT) = 180

(5x) + (3x+4) = 180

8x+4 = 180

8x+4-4 = 180-4

8x = 176

8x/8 = 176/8

x = 22

Note: now that I reached this point I realize that this might be the answer to problem 1; however, I'm not 100% sure because of the incomplete problem.

Use this x value to find angle GAR

angle GAR = 5*x

angle GAR = 5*22

angle GAR = 110

Unfortunately this answer isn't listed. I'm thinking your teacher made another typo.

===================================

Problem 3)

Answer: angle GAR and angle ABQ are corresponding angles.

Thankfully this answer is listed. Corresponding angles are angles that are on the same side of the transversal line and they are either both above or below the parallel lines they are next to. In this case, they are both above the parallel line counerparts.

===================================

Problem 4)

Corresponding angles are congruent as long as we have a set of parallel lines. So that means angle ABQ is equal to angle GAR. So angle ABQ is also 110 degrees

===================================

Problem 5)

angle BAT = angle GAR,  because they are vertical angles

angle BAT = 110

angle BAT = (angle BAD) + (angle DAT)

(angle BAD) + (angle DAT) = angle BAT

(100) + (angle DAT) = 110

angle DAT = 110-100

angle DAT = 10

angle ADB = angle DAT,  because they are alternate interior angles

angle ADB = 10

--------

Final Answer: 10 degrees


5 0
3 years ago
Can someone please help me with my hw 20 points?
Neporo4naja [7]

Answer:

The first equation; x-2y=8

Step-by-step explanation:

Hi there!

We're told that Ty wants to isolate x in one of the equations. To do so in either, he will need to use inverse operations to cancel out values and leave just x remaining on one side of the equation.

In the second equation, he would need to subtract both sides by 6y and then divide both sides by 4 to isolate x. It's a two-step process.

However, in the first equation, he only needs to add 2y to both sides to isolate x.

I hope this helps!

7 0
3 years ago
Read 2 more answers
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