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3 years ago

Factor 64a^2 - 48a + 9. A(8a + 9)(8a - 1) B(8a - 3)^2 C(4a + 3)(16a - 3)

Mathematics

2 answers:

Akimi4 [234]3 years ago

7 0

Answer:

B. (8a-3)^2

Step-by-step explanation:

Hope this helps! :)))

Jobisdone [24]3 years ago

5 0

(8a-3)(8a-3)..........

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What is one website you can visit in order to request free credit report from any of the three bureaus?

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3 years ago

surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo

balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

Tan(58°)*100m = h1 = 160m.

The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 = 196.3m - 160m = 36.3m

6 0

3 years ago

#1 Using the right triangle below, find the cosine of angle A.

motikmotik

Answer: 0.8

Step-by-step explanation:

Using the Cosine formula :

$Cos A = \frac{b^{2}+c^{2}-a^{2}}{2bc}$

$a = 6$

$b = 8$

$c = 10$

substituting into the formula , we have

$Cos A = \frac{8^{2}+10^{2}-6^{2}}{2(8)(10)}$

$Cos A = \frac{64+100-36}{160}$

$Cos A = \frac{164-36}{160}$

$Cos A = \frac{128}{160}$

Therefore :

Cosine of angle A = 0.8

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3 years ago

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3 years ago

Explain how to graph the given piecewise-defined function. Be sure to specify the type of endpoint each piece of the function wi

suter [353]

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3 years ago

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