Let the measure of side AB be x, then, the measue of side AE is given by

.
Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
Solution is supposed to be as follows
<span>u+<span>2 / 3</span><span> u<span>^3/2</span></span>
=r+<span>2 / 3</span><span> r^<span>3/2</span></span> + <span>c</span></span>
Hello :
<span> the axis of symmetry is the line for equation : x = 2
the </span><span>vertex is the point : A (2 , 4)</span>
5.67 (performed on a calculator)