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kvv77 [185]
3 years ago
14

I need heeeeeeeeeeelllllllllllllppppppppppp!?!

Mathematics
2 answers:
fredd [130]3 years ago
7 0
I would have chose B
kati45 [8]3 years ago
3 0

Answer:

I cant give you an answer but hints:

First you gotta know the angles of the triangle

then how many are there

then those lines in the middle is dividing lines so

right angles are 90 degrees

I would go for B then.

if not I'm sorry

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The sum of two numbers is 150 and the ratio of the same two numbers is 3 to 2 . find the bigger number
krek1111 [17]
Ratio- 3: 2

3x + 2x = 150
5x = 150
x = 30

3x is the larger number so plug in the x value with 30.

3x
3 x 30
90

The larger number is 90.

Hope I helped.. ^^
8 0
3 years ago
Read 2 more answers
sipho's dad used 4/11 of the packet of oranges to make juice.The next day he used another 4/11 of the packet of oranges.How many
igomit [66]

9514 1404 393

Answer:

  3/11 were left

Step-by-step explanation:

A packet of oranges is 11/11. Subtracting 4/11 +4/11 = 8/11 from that leaves ...

  11/11 -8/11 = (11 -8)/11 = 3/11

3 elevenths were left.

6 0
3 years ago
Which of following not a way to represent the solution of inequality 5(x + 2) GREATER THAN OR EQUAL TO 7x + 2(x − 1)?
mixer [17]
So because it says NOT a way....I think it's A...Maybe I'm wrong but whatever.
6 0
4 years ago
Read 2 more answers
5. Given: BCDF is a parallelogram; line AB is congruent to line BF
solong [7]
A and E are corresponding angles so A=E
3 0
2 years ago
Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

5 0
3 years ago
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