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Fynjy0 [20]
3 years ago
6

Santa Claus has been experiencing some recent back pain and is unable to carry large bags of toys over his shoulders. As a resul

t, he has decided to use FedEx to deliver many of his gifts this year. FedEx charges a flat rate of $2.50 plus $0.85 per pound. If the cost of sending gifts to the Jones's was $28.85, how much did their gifts weigh?
Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

31 pounds

Step-by-step explanation:

From the information given, you can write the following formula to calculate the total cost of sending gifts:

Total cost of sending gifts=2.50+0.85x, where x is the weight of the gifts in pounds

Also, you know that the total cost of sending gifts is $28.85 and you can replace this value and solve for x:

28.85=2.50+0.85x

28.85-2.50=0.85x

26.35=0.85x

x=26.35/0.85

x=31

According to this, the answer is that the gifts weighed 31 pounds.

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Sure it is. Any function y= f(x) is an exponential one if the constant is raised to the power of x:

y= 5ˣ

y=aˣ

y=(2/3)ˣ
8 0
4 years ago
A shopper bought shoes marked $40.<br> The sales tax is 8%. How much did the<br> shopper pay in all?
anastassius [24]

Answer:

follow step by step to get answer

Step-by-step explanation:

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6 0
3 years ago
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Which is longer 1/4 of line a of line b explain
juin [17]

Answer:

A is smaller than line B.

Step-by-step explanation:

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3 years ago
A bag of marbles can be shared equally among 3, 4, 5, 8 or 10 people with none left over. What is the smallest number of marbles
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Answer:

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4 0
3 years ago
George needs to rent a car for one day. He can rent a Cadillac from Gamma Car Rental for $30.39 per day plus 55 cents per mile.
oksian1 [2.3K]
Call the number of days 'd' and the number of miles 'm'.
(Original, eh ?)

Then the equation for Gamma's price is

                           Price-G = 30.39d + 0.55m

and the equation for Delta's price is

                            Price-D = 50.31d + 0.43m .

We're going to set the prices equal, and find out
what the number of miles is:

                       Price-G = Price-D.

        30.39d + 0.55m  = 50.31d + 0.43m .

Before we go any farther, I'm going to assume that both cases would be
one-day rentals.  My reasons:  ==> the solution for the number of miles
depends on how many days each car was rented for;  ==> even if both
cars are rented for the same number of days, the solution for the number
of miles depends on what that number of days is.

For 1-day rentals, d=1, and

                                        30.39 + 0.55m  =  50.31 + 0.43m .
Beautiful.  Here we go.
Subtract 0.43m
from each side:              30.39 + 0.12m  =  50.31

Subtract 30.39
from each side:                            0.12m  =  19.92

Divide each side by 0.12 :                  m  =  166 .

There it is !  If a car is rented from Gamma for a day, and another car
is rented from Delta for a day, and both cars are driven 166 miles, then
the rental prices for both cars will be the same ... (namely $121.69)
4 0
3 years ago
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