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k0ka [10]
3 years ago
15

HELP PLEASE!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:

-9.661

Step-by-step explanation:

1. substitute -a with 6.05 and do the same with -b

-6.05+(-3.611)

Since they are the same sign, you add.

= -9.661

Tanzania [10]3 years ago
5 0

Answer:

-9.661

Step-by-step explanation:

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-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)− 6 1 ​ ×(− 7 9 ​ )minus, start fraction, 1, divided by, 6, end fraction, times,
sergey [27]

Answer:

  \dfrac{3}{14}

Step-by-step explanation:

The even number of minus signs means the product will be positive. A factor of 3 can be removed to simplify the product. As usual, the numerator of the product is the product of numerators, and the denominator of the product is the product of denominators.

  -\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)=\dfrac{1\cdot 9}{6\cdot 7}=\dfrac{3\cdot 3}{3\cdot 14}=\boxed{\dfrac{3}{14}}

7 0
3 years ago
Read 2 more answers
What is the factor form of r^27 - s^30
Schach [20]

Answer:

(r^9−s^10) (r^18+r^9s^10+s^20)

8 0
3 years ago
E pls help me again
bagirrra123 [75]

Answer:

D

Step-by-step explanation:

14.34 x 21 - 2.40 x 7 = 284.55

3 0
3 years ago
Use the given frequency distribution to find the class width, class midpoint, and class boundaries​
Harman [31]

Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

<h3 /><h3>What is the frequency distribution about?</h3>

Temperature (°F) Frequency

40-44 1

45-49 3

50-54 5

55-59 11

60-64 7

65-69 7

70-74 1

A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:

 Class width = 44 − 40= 4

B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is  seen below:

=  40  - 44 = \frac{40 + 44}{2}   = 42. In a similar way, we find the rest.

C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:

43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5

Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

Learn more about frequency distribution from

brainly.com/question/1094036

#SPJ1

5 0
2 years ago
The probability that house sales will increase in the next 6 months is estimated to be 0.25. The probability that the interest r
marin [14]

Answer:

0.11

Step-by-step explanation:

Probability that house sale will increase = P(A) = 0.25

Probability that interest rate on house loans will go up = P(B) = 0.74

Probability that either house sales will go up or interest rates will go up = P(A or B ) = 0.89

We have to find the probability that neither house sales nor interest rates will increase. This event is the compliment of the event that either house sales will go up or interest rates will go up.

i.e.

Probability that neither house sales nor interest rates will increase = P(A \cup B)^{c}

P(A\cup B)^{c} = 1 - P(A \cup B)

Using the value of P(A U B), we get:

P(A\cup B)^{c} = 1 - 0.89\\\\ P(A\cup B)^{c} = 0.11

The probability that neither house sales nor interest rates will increase during the next 6 months is 0.11

7 0
3 years ago
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