<u><em>Answer:</em></u>
Area of rhombus = 126 m²
<u><em>Explanation:</em></u>
<u>We are given that the two diagonals of the rhombus are:</u>
D₁ = 14 meters and D₂ = 18 meters
<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

<u>Substitute with the given values to get the area as follows:</u>

Hope this helps :)
Answer:
hey:)
12:15-8:15=4hr
17:30-13:00=4:30hr
4+4:30=8:30hr
$11/hr therefore:
8:30×11= 8.5×11=93.5
and now round it to the nearest hundredth:) I hope this was helpful
2(3w-2+w)
=2(4w-2)
=8w-4
the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is <span>2(3w-2+w), and then you just have to simplify that </span>
This is the concept of algebra, given that the area of a rectangular pool is (15x-9), the possible dimensions of the pool by factoring will be:
Area=length×width
Area=(15x-9)
factoring the above we get:
Area=3(5x-3)
therefore the possible dimension will be:
length=5x units
width=3 units
Answer: 16)
(17)
(18)
(19) 3x - 18
<u>Step-by-step explanation:</u>
Inverse is when you swap the x's and y's and then solve for y
16) Given: y = x²
Swapped: x = y²

17) Given: y = 2x + 4
Swapped: x = 2y + 4
x - 4 = 2y

18) Given: y = (x + 2)²
Swapped: x = (y + 2)²
√x = y + 2

19) Given: 
Swapped: 

3(x - 6) = y
3x - 18 = y