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BlackZzzverrR [31]
3 years ago
13

0.000012 write in scientific notion

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0
This is the answer in scientific Notation

1.2 x 10 ^(-5)
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Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.
xxTIMURxx [149]

<u><em>Answer:</em></u>

Area of rhombus = 126 m²

<u><em>Explanation:</em></u>

<u>We are given that the two diagonals of the rhombus are:</u>

D₁ = 14 meters and D₂ = 18 meters

<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

Area = \frac{D_1 * D_2}{2}

<u>Substitute with the given values to get the area as follows:</u>

Area = \frac{14*18}{2}=126 m^2

Hope this helps :)

8 0
2 years ago
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Can anyone figure this out? I’ll give Brainly :)) thank you!
Dennis_Churaev [7]

Answer:

hey:)

12:15-8:15=4hr

17:30-13:00=4:30hr

4+4:30=8:30hr

$11/hr therefore:

8:30×11= 8.5×11=93.5

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8 0
2 years ago
A rectangle has width w and its length is 2 units shorter that 3 times the width
topjm [15]
2(3w-2+w)
=2(4w-2)
=8w-4

the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is <span>2(3w-2+w), and then you just have to simplify that </span>
8 0
3 years ago
The area of a rectangle is pool is (15x-9) square units. Factor 15x-9 to find possible dimensions of the pool
Darya [45]
This is the concept of algebra, given that the area of a rectangular pool is (15x-9), the possible dimensions of the pool by factoring will be:
Area=length×width
Area=(15x-9)
factoring the above we get:
Area=3(5x-3)
therefore the possible dimension will be:
length=5x units
width=3 units
8 0
3 years ago
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Please helppp meeeeee
alexira [117]

Answer:  16) \bold{\sqrt{x}}        (17) \bold{\dfrac{x-4}{2}}        (18) \bold{\sqrt{x}-2}       (19)  3x - 18

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and then solve for y

16) Given: y = x²

Swapped: x = y²

                \bold{\sqrt{x} =y}

17) Given:  y = 2x + 4

Swapped: x = 2y + 4

            x - 4 = 2y

            \bold{\dfrac{x-4}{2}=y}

18) Given:  y = (x + 2)²

Swapped: x = (y + 2)²

               √x = y + 2

        \bold{\sqrt{x}-2=y}

19) Given:  y=\dfrac{1}{3}x+6

Swapped: x=\dfrac{1}{3}y+6

            x - 6 = \dfrac{1}{3}y

            3(x - 6) = y

            3x - 18 = y

4 0
2 years ago
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