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yuradex [85]
3 years ago
13

Can I have help this is due on Sunday at 11:59pm central daylight time.

Mathematics
1 answer:
rodikova [14]3 years ago
5 0

Answer:

sorry your on your own,  becuase if i tell you, next test you take with this stuff on it you wont know what the formulas are, look up some formulas, and to speed things up go to https://soupcalculator they have EVERY claculator ever needed

Step-by-step explanation:

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What is (x^2+2)(5x+1) multipyed
babymother [125]

Answer:

5x^{3}  +  x^{2}  + 1 0  + 2 Is the correct answer

Step-by-step explanation:

in pic

<em><u>(Credit: Symbolab)</u></em>

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(Hope this helps can I pls have brainlist (crown)☺️)

3 0
3 years ago
Read 2 more answers
X – 3y = 13<br> 2x + 4y = -4<br> What is the solution?
MAVERICK [17]
X=4 Y=3 I hope this helped I don’t know if it is fully right
7 0
4 years ago
Read 2 more answers
Given that (-4,1) is on the graph of f(x), find the corresponding point for the function 4f(x)
AVprozaik [17]
F(-4) = 1
4f(-4) = 4

The point of interest is (-4, 4).
8 0
3 years ago
The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?
Hunter-Best [27]
Oven tray: 600 mm by 500 mm
cake tin: 25 cm in diameter

convert mm to cm.

1 cm = 10 mm

600mm * 1cm/10mm = 60cm
500mm * 1cm/10mm = 50cm

Area of oven tray = 60cm * 50cm  = 3,000 cm²
Area of cake tin = 3.14 * (25cm/2)² = 3.14 * (12.5cm)² = 3.14 * 156.25cm² = 490.625 cm²

3,000cm² ÷ 490.625cm² = 6.11 or 6 cake tins can fit on the oven tray at one time.
3 0
4 years ago
Bill and George go target shooting together. Both shoot at atarget at the same time. Suppose Bill hits the target withprobabilit
german

Answer: (a) \frac{2}{9}       (b) \frac{6}{41}

Step-by-step explanation:

(a) P( Bill hitting the target) = 0.7        P( Bill not hitting the target) = 0.3

    P( George hitting the target) = 0.4     P(George not hitting the target) = 0.6

Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3

                                                                                            = 0.54

Chances that George hit the target is = 0.4 x 0.3 = 0.12

So given that exactly one shot hit the target, probability that it was George's shot = \frac{0.12}{0.54} = \frac{2}{9} .

(b) The numerator in the second part would be the same as of (a) part which is 0.12.

The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.

Given that the target is hit,probability that George hit it =                                                 \frac{0.4\times 0.3}{0.7\times 0.6 +0.4\times 0.3+0.4\times 0.7}  = = \frac{6}{41}                                                                        

                                                                                           

6 0
3 years ago
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