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2 years ago

7

Elaine had StartFraction 5 Over 8 EndFraction of a pizza left after lunch. She told 5 of her friends that they could share the r

est. What fraction of the pizza did each of her friends get if they split it evenly?
A pizza with 8 slices. 5 slices are shaded.
StartFraction 1 Over 8 EndFraction
StartFraction 1 Over 5 EndFraction
StartFraction 3 Over 8 EndFraction
StartFraction 3 Over 5 EndFraction

2 answers:

Alex_Xolod [135]2 years ago

7 0

Answer:

A. 1/8

Step-by-step explanation:

did the quiz & got it right.

good luck!

Lunna [17]2 years ago

6 0

Startfraction 3 over 8 endfraction

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39) The length of a rectangle is (2x - 1) and the width is (3x2 -5x + 2). Find the area of the rectangle.

Nuetrik [128]

Answer:

(4,-2)

Step-by-step explanation:

Start off by doing everything in the parenthesis which is everyone of them so 2x-1=-2 , your problem then should look like this:

-2(3x2-5x+2) carry the 2 over so multiply the 2 to everything so

(-6x-4+10x+2) add like numbers

10x+-6=4

-4+2=-2

(4,-2)

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1 year ago

Mr. Jameson will stain the deck in his backyard the deck has an area of 752.4 square feet if the deck is 33 ft long how wide is

Sergio039 [100]

752.4/33 = width
Plug that into your calculator and you'll get the answer.
Justification: legnth times width = area, so area divided by length = width

8 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

A sheet of plastic has an area of 35 square cm. If the sheet is 5 cm thick, what is the volume?

Andre45 [30]

Answer:

175 cm³

Step-by-step explanation:

Volume = área * thick

Volume = 35cm² * 5cn

Volume = 175 cm³

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2 years ago

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Can someone help me with this math homework please!

statuscvo [17]

Answer:

1 = Input G

2 = Input F

3 = Input H

Step-by-step explanation:

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2 years ago