Elaine had StartFraction 5 Over 8 EndFraction of a pizza left after lunch. She told 5 of her friends that they could share the r
2 answers:
You might be interested in
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:
Step-by-step explanation:
Slope-intercept form: y = mx + b
Slope formula:
Given points: (3, -7), (7, 2)
(3, -7) = (x1, y1)
(7, 2) = (x2, y2)
To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.
First, let's find the slope. To do this, input the given points into the slope formula:
Simplify:
2 - (-7) = 2 + 7 = 9
7 - 3 = 4
The slope is .
To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:
The y-intercept is .
Now that we know the slope and the y-intercept, we can write the equation: