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SOVA2 [1]
3 years ago
12

Plz help !! Needed to graduate

Mathematics
2 answers:
OleMash [197]3 years ago
8 0

\frac{  \sqrt{ - 12} }{ \sqrt{6} }  = i \sqrt{2}
the answer to the question
e-lub [12.9K]3 years ago
5 0

Answer:  c. i√2

<u>Step-by-step explanation:</u>

\dfrac{\sqrt{-12}}{\sqrt6}=\dfrac{\sqrt6\cdot \sqrt{-2}}{\sqrt6}=\sqrt{-2}=\boxed{i\sqrt2}

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4 0
3 years ago
Read 2 more answers
The difference 2/5(d−10)−2/3(d+6) is
spin [16.1K]

Let's simplify step-by-step.

2/5(d−10)−2/3(d+6)

Distribute:

= (2/5)(d)+(2/5)(−10)+ −2/3d+ −4

= 2/5d+−4+ −2/3d+ −4

Combine Like Terms:

= 2/5d+−4+ −2/3d+ −4

= −4/15d+−8

And your answer is...

= −4/15d+−8

plz mark me as brainliest if this helped :)

6 0
3 years ago
Read 2 more answers
Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
andrew11 [14]

Differentiating both sides of

x^2 + 2xy - y^2 + x = 20

with respect to x yields

2x + 2y + 2x \dfrac{dy}{dx} - 2y \dfrac{dy}{dx} + 1 = 0 \\\\ \implies (2x-2y) \dfrac{dy}{dx} = -1 - 2x - 2y \\\\ \implies \dfrac{dy}{dx} = \dfrac{1 + 2x + 2y}{2(y-x)}

At the point (3, 4) (so x=3 and y=4), the tangent line has slope

\dfrac{dy}{dx} = \dfrac{1 + 2\times3 + 2\times4}{2(4-3)} = \dfrac{15}2

Then the tangent line to (3, 4) has equation

y - 4 = \dfrac{15}2 (x - 3) \implies \boxed{y = \dfrac{15}2 x - \dfrac{37}2}

7 0
2 years ago
Of Canada's total area of 9,976,140 km² , 755,170 km² is water. To the nearest tenth of percent, what part of Canada is water?
algol13

Answer:

755170/9976140 x 100

= 7.56976 %

= 8 % or (to the nearest 10th 10%) of Canada

Step-by-step explanation:

5 0
3 years ago
What is f(-2) of the function given below? *<br> f(x) = 3x2 - 4x + 1
slava [35]

Answer:

f(-2) = 21

Step-by-step explanation:

Step 1: Define

f(x) = 3x² - 4x + 1

f(-2) is x = -2

Step 2: Substitute and Evaluate

f(-2) = 3(-2)² - 4(-2) + 1

f(-2) = 3(4) + 8 + 1

f(-2) = 12 + 9

f(-2) = 21

5 0
3 years ago
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