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Oxana [17]
2 years ago
13

Find the slope intercept form of slope-2 which passes through (-5,1)

Mathematics
1 answer:
dusya [7]2 years ago
6 0

Answer:

y=2x+11

Step-by-step explanation:

So we know that the slope is 2 and the lines passes through the point (-5,1).

We can use the point-slope form. The point-slope form is:

y-y_1=m(x-x_1)

Where m is the slope and (x₁, y₁) is a point.

So, let's substitute 2 for m and (-5,1) for (x₁, y₁), respectively. Therefore:

y-(1)=2(x-(-5))

Simplify:

y-1=2(x+5)

Distribute the 2:

y-1=2x+10

Add 1 to both sides:

y=2x+11

So, the equation of our line is:

y=2x+11

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1/2 ; 1/4

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In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
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Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

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m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

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